A could be 2 while B could be 3, so -2a+3b turns into -4+9, which equals 5.
From what I know you can't really solve a a single equation with two-variables so it's just a matter of trial and error.
Just try plugging in a small number like 2 for a just to try it and you get 8b^2=72.
Divide everything by 8 to isolate b and you get that b^2=9.
Square root everything and you'll find that b=3. This is just one possible combination, I'm sure there are many more but this is obviously the one that was intended to be found.
Now that we know that a=2 and b=3 just plug them into the equation.
-2(2)+3(3)=?
-4+9=?
5
Sorry about having to use this ^ symbol, the equation maker is not working.
Answer:
$7562.50
Step-by-step explanation:
Answer:
<em>Zeina had 35 books and Ali had 5 books</em>
Step-by-step explanation:
<u>Equations</u>
We know Zeina has seven times as many books as Ali. If we call
x = Number of books Ali has
Then Zeina has
7x = Number of books Zeina has
We also know if Zeina gave Ali 15 books, they would have the same number of books, thus:
x + 15 = 7x - 15
Adding 15:
x + 15 +15 = 7x
Subtracting x:
15 +15 = 7x - x
Operating:
30 = 6x
Dividing by 6:
x = 30 / 6
x =5
7x = 35
Thus Zeina had 35 books and Ali had 5 books
Step-by-step explanation:
am-an+bm-bn
m(a+b)-n(a+b)
(m-n)(a-b)
<span>b.14(7x3 - 1)13(21x2) + 49(x2 + 50)48(2x)</span>
