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2 years ago

WHAT IS THE MEASURE OF ANGLE A

Mathematics

1 answer:

madreJ [45]2 years ago

3 0

Answer:

∠A = 100

∠B = 50

∠C = 30

Step-by-step explanation:

Sum of all angles of triangle = 180

∠A + ∠B + ∠C = 180

2x +x + x - 20 = 180 {Combine like terms}

4x - 20 = 180

Add 20 to both sides

4x = 180 + 20

4x = 200

Divide both sides by 4

x = 200/4

x = 50

∠A = 2x = 2*50 = 100

∠B = x = 50

∠C = x - 20 = 50 - 20 = 30

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WILL GIVE BRAINLIEST

Makovka662 [10]

Answer:

its is 50+4hr cause it is more reasonable

Step-by-step explanation:

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2 years ago

I don’t know , help you

Sphinxa [80]

A negative sign (-)

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2 years ago

If G = {(-1, 7),(-8, 2),(0, 0),(6, 6)), then the range of G is

lana66690 [7]

Answer:

$\{0, 2, 6, 7\}$

Step-by-step explanation:

You are given the relation $G = \{(-1, 7),(-8, 2),(0, 0),(6, 6)\}$

This means that

$f(-1)=7\\ f(-8)=0\\f(0)=0\\f(6)=6$

The input values of this relation are $-1,\ -8,\ 0,\ 6$ , so the domain of this relation is $\{-8,-1,0,6\}$

The output values of this relation are $7,\ 2,\ 0,\ 6$ , so the range of this relation is $\{0, 2, 6, 7\}$

8 0

3 years ago

Find the exact area of a circle with a dimeter of 5 yards. Use 3.14 for pi

kenny6666 [7]

Answer:

$A = 6.25(pi)$

$A$ ~ $19.63495$

Step-by-step explanation:

The formula for finding the area of a circle is;

$A = (pi)r^2$

Where ( $A$ ) represents the area of the circle, ( $pi$ ) represents the value ( $3.1415...$ ) and ( $r$ ) represents the radius of the circle. As per its definition, the diameter is the largest cord or line segment that can be drawn through a circle, the diameter always passes through the center of a circle. The radius ( a line segment that can be drawn from the center of the circle to any side of the circle) is always half of the diameter.

This means that the radius for the given circle is ( $2.5$ ), since ( $5$ ÷ $2=2.5$ )

Substitute these values into the equation and solve for the area of the circle.

$A = (pi)r^2\\\\A = (pi)(2.5)^2\\\\A = (pi)6.25\\$

$A$ ~ $19.63495$

7 0

3 years ago

The table below shows data for a class's mid-term and final exams:

lina2011 [118]

Mid term :
Q1 = (88 + 85)/2 = 86.5
Q2 = (92 + 95)/2 = 93.5
Q3 = 100
IQR = Q3 - Q1 = 100 - 86.5 = 13.5

final exams :
Q1 = (65 + 78)/2 = 71.5
Q2 = (88 + 82)/2 = 85
Q3 = (95 + 93)/2 = 94
IQR = Q3 - Q1 = 94 - 71.5 = 22.5

so the final exams has the largest IQR

5 0

2 years ago

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