Answer:
x = 21
Step-by-step explanation:
the angles 5x - 35 and 3x + 7 are vertical angles and congruent, thus
5x - 35 = 3x + 7 ( subtract 3x from both sides )
2x - 35 = 7 ( add 35 to both sides )
2x = 42 ( divide both sides by 2 )
x = 21
Answer:
(d) (7, -5)
Step-by-step explanation:
The x-coordinate is listed first in an ordered pair. It is found on the horizontal scale. The point is on the grid line halfway between 6 and 8, so is presumed to have an x-coordinate of 7.
The y-coordinate is listed second in an ordered pair. It is found on the vertical scale. The point is on the grid line halfway between -4 and -6, so is presumed to have a y-coordinate of -5.
The coordinates of point A are (x, y) = (7, -5).
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<em>Additional comment</em>
As in the case here, you will often run across graphs that don't have markings on every grid line You are expected to be able to figure out the value of a grid line based on the spacing of the marked lines.
It is a good idea to get familiar with reading coordinates of a point on a graph, as you will be doing it a lot.
First I chose two points on the line that fall on 2 intervals or 2 lines. Then if found the slope of the two points. Using the slope and one of the points I pugged the numbers into an equation to solve for b. Once I found b I wrote an equation using b and the slope.
y=-2/3+300
steps:
(250,200)(300,100)
100-200/300-150
-100/150 or -2/3
100=-2/3(300)+b
100=-200+b
300=b
y=-2/3b+300
Answer:
<h2><em><u>Option</u></em><em><u> </u></em><em><u>C</u></em></h2>
Step-by-step explanation:
<em><u>Here</u></em><em><u>,</u></em>
<em>[</em><em>Taking</em><em> </em><em>'</em><em>A'</em><em> </em><em>=</em><em> </em><em>'</em><em>a'</em><em>]</em>

<em><u>Then</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>'</u></em><em><u>r</u></em><em><u>'</u></em><em><u>,</u></em>




<em><u>Hence</u></em><em><u>,</u></em>
<em><u>Option</u></em><em><u> </u></em><em><u>C</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>correct</u></em><em><u> </u></em><em><u>.</u></em>