Find the inverse function for

Compare and contrast the methods used by African and Asian nations to achieve independence.

goblinko [34]

Answer: Decolonization as a result of World War II.

Step-by-step explanation:

With the end of World War II, the process of decolonization of the African and Asian continents began. It is the result of the destruction brought with it by World War II, but also by the liberalization that took place in Europe after World War II. In this context, it isn't effortless to point out the particular methods used by nations on these two continents. Decolonization is, however, an independent will and intervention of European countries.

Yet the colonization of nations was not entirely passive in terms of resistance to the European invaders. There were several uprisings against the colonists. However, what characterizes both fights for independence is the emergence of nationalism. This is the pattern that African and Asian countries have taken over from Europeans. The form of resistance also consisted in the fact that there was a specific political will on the part of certain domestic elites, as in the case of the West African National Congress or the South African National Congress.

A particular form of struggle for independence existed in India. This Asian country led its effort by methods of civil disobedience, non-payment of taxes, and refusal to work. The creator of this form of struggle was the leader of the Indian independence movement Mahatma Gandhi. An example of diminishing "third country" influence was an international intervention. Such an example is evident in Korea, where the United States and the Soviet Union eliminated Japanese colonial pretensions by their impact.

5 0

2 years ago

(x + 4)(2x - 1)(x-3)=0

ale4655 [162]

Answer:

2x^{3} + x^{2} - 25x + 12

Step-by-step explanation:

There are three different enclosed brackets.

First multiply two of the brackets, then multiply the third by the answer

6 0

3 years ago

Suppose that a box contains r red balls and w white balls. Suppose also that balls are drawn from the box one at a time, at rand

dybincka [34]

Answer: Part a) $P(a)=\frac{1}{\binom{r+w}{r}}$

part b) $P(b)=\frac{1}{\binom{r+w}{r}}+\frac{r}{\binom{r+w}{r}}$

Step-by-step explanation:

The probability is calculated as follows:

We have proability of any event E = $P(E)=\frac{Favourablecases}{TotalCases}$

For part a)

Probability that a red ball is drawn in first attempt = $P(E_{1})=\frac{r}{r+w}$

Probability that a red ball is drawn in second attempt= $P(E_{2})=\frac{r-1}{r+w-1}$

Probability that a red ball is drawn in third attempt = $P(E_{3})=\frac{r-2}{r+w-1}$

Generalising this result

Probability that a red ball is drawn in [tex}i^{th}[/tex] attempt = $P(E_{i})=\frac{r-i}{r+w-i}$

Thus the probability that events $E_{1},E_{2}....E_{i}$ occur in succession is

$P(E)=P(E_{1})\times P(E_{2})\times P(E_{3})\times ...$

Thus $P(E)$ = $\frac{r}{r+w}\times \frac{r-1}{r+w-1}\times \frac{r-2}{r+w-2}\times ...\times \frac{1}{w}\\\\P(E)=\frac{r!}{(r+w)!}\times (w-1)!$

Thus our probability becomes

$P(E)=\frac{1}{\binom{r+w}{r}}$

Part b)

The event " r red balls are drawn before 2 whites are drawn" can happen in 2 ways

1) 'r' red balls are drawn before 2 white balls are drawn with probability same as calculated for part a.

2) exactly 1 white ball is drawn in between 'r' draws then a red ball again at $(r+1)^{th}$ draw

We have to calculate probability of part 2 as we have already calculated probability of part 1.

For part 2 we have to figure out how many ways are there to draw a white ball among (r) red balls which is obtained by permutations of 1 white ball among (r) red balls which equals $\binom{r}{r-1}$

Thus the probability becomes $P(E_i)=\frac{\binom{r}{r-1}}{\binom{r+w}{r}}=\frac{r}{\binom{r+w}{r}}$

Thus required probability of case b becomes $P(E)+ P(E_{i})$

= $P(b)=\frac{1}{\binom{r+w}{r}}+\frac{r}{\binom{r+w}{r}}\\\\$

7 0

3 years ago

Use synthetic division and remainder theorem p(x) = 3x^3 - 5x^2 - x + 2. p(-1/3)=

Alik [6]

Answer:

5/3

Step-by-step explanation:

-1/3 goes on the outside and since we have our polynomial in standard form with no in between terms missing, 3,-5,-1,2 go inside because they are the coefficients of our polynomial.

-1/3 | 3 -5 -1 2

|

-------------------------------------

First step bring the 3 down inside. (3+0=3)

-1/3 | 3 -5 -1 2

|

-------------------------------------

3

Whatever goes below the bar, must be multiplied by outside number and put directly below next number inside.

-1/3 | 3 -5 -1 2

| -1

-------------------------------------

3

The numbers lined up vertically are added to get the numbers underneath the bar.

-1/3 | 3 -5 -1 2

| -1

-------------------------------------

3 -6

Again any number below the bar gets multiply to the number outside.

-1/3 | 3 -5 -1 2

| -1 2

-------------------------------------

3 -6

Again the numbers lined up vertically above the bar get added to get the number that goes underneath the bar there.

-1/3 | 3 -5 -1 2

| -1 2

-------------------------------------

3 -6 1

Multiply to outside number 1(-1/3)=-1/3.

This goes under the 2 inside.

-1/3 | 3 -5 -1 2

| -1 2 -1/3

-------------------------------------

3 -6 1

The last number we are fixing to be put is the remainder of (3x^3-5x^2-x+2)/(x+1/3) or you could say it is the value of p(-1/3) since:

P(x)/(x-c)=Q(x)+R/(x-c)

Multiply both sides by (x-c):

P(x)=Q(x)(x-c)+R

If you evaluate P at x=c, we get R:

P(c)=Q(c)(c-c)+R

P(c)=Q(c)*0+R

P(c)=R.

Let's finish:

-1/3 | 3 -5 -1 2

| -1 2 -1/3

-------------------------------------

3 -6 1 5/3

This means p(-1/3)=5/3.

We could have also got this by directly plugging in (-1/3) for x into 3x^3-5x^2-x+2.

7 0

3 years ago

Ronald is 26 years old and starting an IRA (individual retirement account). He is going to invest $200 at the beginning of each

Licemer1 [7]

The formula for the future value A, given annual interest rate r, number of years t, and deposit amount P can be written as

... A = P(1 +r/12)((1+r/12)^(12t) -1)/(r/12)

Filling in the given numbers, you have

... A = 200(1+.0275/12)((1+.0275/12)^(12·39) -1)/(.0275/12) ≈ 167,868.30

The appropriate choice is $167,868.30.

_____

The formula is the one for the sum of a geometric series. It can be useful to consider the last deposit made as the first term of the series.

6 0

2 years ago

Find the inverse function for ​

Find the inverse function for