Answer:
n = -5
Step-by-step explanation:
Solve for n:
n + 2 = 4 n + 17
Hint: | Move terms with n to the left hand side.
Subtract 4 n from both sides:
(n - 4 n) + 2 = (4 n - 4 n) + 17
Hint: | Combine like terms in n - 4 n.
n - 4 n = -3 n:
-3 n + 2 = (4 n - 4 n) + 17
Hint: | Look for the difference of two identical terms.
4 n - 4 n = 0:
2 - 3 n = 17
Hint: | Isolate terms with n to the left hand side.
Subtract 2 from both sides:
(2 - 2) - 3 n = 17 - 2
Hint: | Look for the difference of two identical terms.
2 - 2 = 0:
-3 n = 17 - 2
Hint: | Evaluate 17 - 2.
17 - 2 = 15:
-3 n = 15
Hint: | Divide both sides by a constant to simplify the equation.
Divide both sides of -3 n = 15 by -3:
(-3 n)/(-3) = 15/(-3)
Hint: | Any nonzero number divided by itself is one.
(-3)/(-3) = 1:
n = 15/(-3)
Hint: | Reduce 15/(-3) to lowest terms. Start by finding the GCD of 15 and -3.
The gcd of 15 and -3 is 3, so 15/(-3) = (3×5)/(3 (-1)) = 3/3×5/(-1) = 5/(-1):
n = 5/(-1)
Hint: | Simplify the sign of 5/(-1).
Multiply numerator and denominator of 5/(-1) by -1:
Answer: n = -5
The difference in Trayvon's weight between Saturn and earth is 12922 lb
Step-by-step explanation:
Step 1:
It is given that Trayvon weighs 142 lb in earth. His weight must be multiplied by 92 to get the weight in Saturn.
Weight of Trayvon in Saturn = 142 lb * 92 = 13064 lb
Step 2:
Weight of Trayvon in earth = 142 lb
Weight of Trayvon in Saturn = 13064 lb
Difference in Trayvon's weight between Saturn and earth is 13064 - 142 = 12922 lb
Step 3:
Answer:
The difference in Trayvon's weight between Saturn and earth is 12922 lb
Answer:
Graphs A and B
Step-by-step explanation:
Graphs A & B are using x-values 1-6 and stop there, which is what the domain is trying to find. Though, for the other graphs, these graphs are rather starting at 1 via the domain, while not going up to 6 on the domain.
Answer:
Given: ∆ABC with the altitudes from vertex B and C intersect at point M, so that BM = CM.
To prove:∆ABC is isosceles
Proof:-Let the altitudes from vertex B intersects AB at D and from C intersects AC at E( with reference to the figure)
Consider ΔBMC where BM=MC
Then ∠CBM=∠MCB......(1)(Angles opposite to equal sides of a triangle are equal)
Now Consider ΔDMB and ΔCME
∠D=∠E.......(each 90°)
BM=MC...............(given)
∠CME=∠BMD........(vertically opposite angles)
So by ASA congruency criteria
ΔDMB ≅ ΔCME
∴∠DBM=∠MCE........(2)(corresponding parts of a congruent triangle are equal)
Adding (1) and (2),we get
∠DBM+∠CBM=∠MCB+∠MCE
⇒∠DBC=∠BCE
⇒∠B=∠C⇒AB=AC(sides opposite to equal angles of a triangle are equal)⇒∆ABC is an isosceles triangle .
