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2 years ago

2. Which of the following graphs show a function with domain 1 ≤ x ≤ 6? Select two that apply.

Mathematics

1 answer:

borishaifa [10]2 years ago

7 0

Answer:

Graphs A and B

Step-by-step explanation:

Graphs A & B are using x-values 1-6 and stop there, which is what the domain is trying to find. Though, for the other graphs, these graphs are rather starting at 1 via the domain, while not going up to 6 on the domain.

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Which expression is equal to 4 (2+3) ?<br><br><br> 1. 2+12<br> 2. 4+5<br> 3. 8+3<br> 4. 8+12

allsm [11]

4. 8+12=20

4 (2+3)
First you add 2+3 and get 5
Next, since the 5 is now in the parentheses, it indicates that you have to multiply
Finally, 5 times 4=20

5 0

3 years ago

Read 2 more answers

1 + tanx / 1 + cotx =2

Lera25 [3.4K]

Answer:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

1 + cot(x) + tan(x) = 2

Multiply both sides of 1 + cot(x) + tan(x) = 2 by tan(x):

1 + tan(x) + tan^2(x) = 2 tan(x)

Subtract 2 tan(x) from both sides:

1 - tan(x) + tan^2(x) = 0

Subtract 1 from both sides:

tan^2(x) - tan(x) = -1

Add 1/4 to both sides:

1/4 - tan(x) + tan^2(x) = -3/4

Write the left hand side as a square:

(tan(x) - 1/2)^2 = -3/4

Take the square root of both sides:

tan(x) - 1/2 = (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

tan(x) = 1/2 + (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Take the inverse tangent of both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) = 1/2 - (i sqrt(3))/2

Take the inverse tangent of both sides:

Answer: x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

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3 years ago

How do you solve 21÷1/3

nordsb [41]

Answer:

Step-by-step explanation:

<u>When dividing by a fraction, it is the same a multiplying that fraction but the reciprocal of it.</u>

21 / 1/3 is same as 21 * 3/1

Answer: 63

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3 years ago

A strobe light is located at the center of a square dance room. the rotating light is 40 feet from each of the square walls and

Effectus [21]

The equation of the rotating light is an illustration of a secant function

The equation that represents the distance between the center of the circle and the light source is $d(t) = 40\sec(\frac{\pi}{3}t)$

<h3>How to determine the equation</h3>

The equation is a secant function represented by

$y =A\sec(Bt)$

Where:

A represents the amplitude

So, we have:

$A = 40$ --- the distance of the light from each square wall

B represents the period, and it is calculated as:

$B = \frac{2\pi}{T}$

The light completes its full rotation every 6 seconds.

This means that,

T = 6

So, we have:

$B = \frac{2\pi}{6}$

Simplify

$B = \frac{\pi}{3}$

Substitute values for A and B in $y =A\sec(Bt)$

$y = 40\sec(\frac{\pi}{3}t)$

Rewrite as a function

$d(t) = 40\sec(\frac{\pi}{3}t)$

Hence, the equation that represents the distance between the center of the circle and the light source is $d(t) = 40\sec(\frac{\pi}{3}t)$

Read more about trigonometry functions at:

brainly.com/question/1143565

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2 years ago

Write the ratio as a fraction in simplest form 25 to 45

brilliants [131]

Answer:

5/9

Step-by-step explanation:

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3 years ago