Answer:
5.) y = 170t
6.) By finding the common rates (slope) (rise over run or y/x)
7a.) Car two isn't going at the constant speed
7b.) They relate by they would still carry the same factors 40mph(from car#2), and 80mph (from car #4) have a common factor of 40 and 35mph (from car #2) and 70mph (from car #4) would have a common factor of 35)
Step-by-step explanation:
(for #5) "t" would mean time as in for hours and the 170 is considered as "m" in the equation of (y=mt+b) and there isn't a starting point of when the bullet trained have already drove (which would have been the number for "b")
So your equation for this would have been y=170t
(For #6) in order for the table or the relationship to be proportional, there must be a constant slope, so the equation would be (when doing it algebraically)
or there is a constant adding (like for example in car 3, the y sections would add by 20 not multiply)
( Or when looking at the table)
for every pair, when you for every pair, it should led you to the same number
so in car 2, everything had the constant speed of 35mph except when dividing for 800/20, it gave us 40mph instead of 800
(For #7a) same thing for #6 but i was using the question from 7a to explain the explanation for #6
(For #7b) (I hope it was easy to understand on what I was talking about)
(Helper's note: I hope it was easy to understand, I tried my best to explain with words [as you can see not good at explaining in words but in numbers haha] )