The Answer to your problem is:
0.8
The triangle inequality applies.
In order for ACD to be a triangle, the length of AC must lie between CD-DA=0 and CD+DA=8.
In order for ABD to be a triangle, the length of AC must lie between BC-AB=3 and BC+AB=9.
The values common to both these restrictions are numbers between 3 and 8. Assuming we don't want the diagonal to be coincident with any sides, its integer length will be one of ...
{4, 5, 6, 7}
4(x+7) becomes 4x+28 you multipli the 4 in parentheses ans 2(x+7) becomes 2x+14
4x+28=2x+14 you move the x termes to the left and other numbers to the right look:
4x-2x=14-28 when you change the sides always change the sign +or-
2x=-14
2x/2=-14/2
X=-7
Answer:
- A) A = 27.3°, B = 56.1°, C = 96.6°
Step-by-step explanation:
<u>Use the Law of Cosines:</u>
- A = arccos [(b² + c² - a²)/(2bc)] = arccos [(13.2² + 15.8² - 7.3²)/(2*13.2*15.8)] = 27.3°
- B = arccos [(a² + c² - b²)/(2ac)] = arccos [(7.3² + 15.8² - 13.2²)/(2*7.3*15.8)] = 56.1°
- C = 180° - (A + B) = 180° - (27.3° + 56.1°) = 96.6°
Correct choice is A.
