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The speed of wind and plane are 105 kmph and 15 kmph respectively.
<u>Solution:</u>
Given, it takes 6 hours for a plane to travel 720 km with a tail wind and 8 hours to make the return trip with a head wind.
We have to find the air speed of the plane and speed of the wind.
Now, let the speed wind be "a" and speed of aeroplane be "b"
And, we know that, distance = speed x time.

Now at head wind → 
So, solve (1) and (2) by addition
2a = 210
a = 105
substitute a value in (1) ⇒ 105 + b = 120
⇒ b = 120 – 105 ⇒ b = 15.
Here, relative speed of plane during tail wind is 120 kmph and during head wind is 90 kmph.
Hence, speed of wind and plane are 105 kmph and 15 kmph respectively.
X+10=18. |-10 from both sides
x+10-10=18-10
x=8
Step-by-step explanation:
Given that:-
So, we can concert 15 minutes to hours.
So,
60 minutes = 1 hour
1 minute = 1/60
15 minutes =

Okay, now we will apply first for 0.4 hours.





Now, second one:-



Hope it helps :D
Answer:
Step-by-step explanation:
Start box
180 = 89+42+x
180-89-42=x
49 = x
2nd box
180 = 84+58+x
180-84-58=x
38 = x
3rd box
180=74+2x
180-74=2x
106/2 = x
53 = x
4th box
180=102+2x
180-102=2x
78/2 = x
39 = x
4th box
180 = 73+81 +x
180-73-81=x
26 = x
5th box
180=2*54+x
180 - 2*54 = x
72 = x
6th box
180=62-2x
180-62=2x
118=2x
118/2=x
59 = x
7th box
180 = 2*68 + x
180-2*68=x
44 = x