Hello.
-7h + 2(-4h + 5) > -4h + 1 + 10 ; solve for h
Our first step is to get rid of all the parenthesis. We can do this by simplifying everything out.
-7h - 8h + 10 > -4h + 11
Add like terms.
-15h + 10 > -4h + 11
Now, we must isolate our variables. We do this by moving all variables to one side and moving our other numbers to the other.
Subtract 10 from both sides. Then, add 4h to both sides.
-15h + 4h > 11 - 10
Simplify.
-h > 1
Divide both sides by -1.
However, keep in mind that when dividing with a negative, you must change the sign. Therefore, > turns into <
-h ÷ -1 < 1 ÷ -1
h < -1
Answer:
3
Step-by-step explanation:
Given that:
Integers : x, x + 1, x + 2
6x - 2(x + 1) = (x+2) + 5
6x - 2x - 2 = x + 2 + 5
4x - 2 = x + 7
4x - x = 7 + 2
3x = 9
x = 9/3
x = 3
First integer = x = 3
2nd integer = x + 1 = 3+1 = 4
3rd Integer = x + 1 + 1 = 3 + 2 = 5
<u>Question 1</u>
If we let 
, then 
.
Also, as 
bisects 
, this means 
.
Thus, by the intersecting chords theorem,
However, as distance must be positive, we only consider the positive case, meaning FE=9
<u>Question 2</u>
If we let CE=x, then because AB bisects CD, CE=ED=x.
We also know that since FB=17, the radius of the circle is 17. So, this means that the diameter is 34, and as AE=2, thus means EB=32.
By the intersecting chords theorem,
However, as distance must be positive, we only consider the positive case, meaning CE=8
Answer:
128√5/3 mm³
Step-by-step explanation:
Since we are not told what to find, we can as well look for the volume of the pyramid
Volume of a square pyramid: V = (1/3)a²h
a is the side length of the square
h is the height of the pyramid
Given
a = 8mm
l² = (a/2)² + h²
l² = (a/2)² + h²
6² = (8/2)² + h²
h² = 6² - 4²
h² = 36 - 16
h² = 20
h = √20
Volume of a square pyramid = (1/3)*8²*√20
Volume of a square pyramid = 1/3 * 64 * 2√5
Volume of a square pyramid = 128√5/3 mm³
