Ask question

Ask question

All categories

3 years ago

14

Lorraine writes the equation shown. x squared + y minus 15 = 0 She wants to describe the equation using the term relation and th

e term function.

2 answers:

Colt1911 [192]3 years ago

8 0

Answer:

x=2 y=11

Step-by-step explanation:

Lina20 [59]3 years ago

8 0

X=2 Y=11

Step-by-step explanation:

I copied the other person

OOF

You might be interested in

Can you please explain how to solve this?

BlackZzzverrR [31]

Answer:

18

Step-by-step explanation:

hello,

as this is a parallelogram we can write that BE = DE so

15x + 4 = 9x + 6

<=> 15x - 9x + 4 = 6

<=> 6x = 6 - 4 = 2

<=> x = 2/6 = 1/3

so BE = DE = 15/3+4=5+4=9

so BD = BE + DE = 9 + 9 = 18

the correct answer is 18

hope this helps

7 0

4 years ago

Trina invited 60 people to her party and 42 said they would attend. What percent of people said they were NOT able to attend? Pl

Llana [10]

1. simplify 42/60 to 7/10 (42/60 divided by 2 is 21/30, 21/30 divided by 3 is 7/10)
2. if 10 x 10 = 100 than 7 x 10 = 70 so that would make it 70/100 which is 70%
so 70% is the answer

Hope this helps ;)
Please don't forget to mark as brainliest answer!

5 0

3 years ago

Read 2 more answers

Decrease 620 by 10%

julia-pushkina [17]

Answer:

682

Step-by-step explanation:

620, percentage decreased by - 10% (percent) of its value = 682

6 0

3 years ago

6 times 9+6+9 =? <br>Pls help

Nata [24]

144

If you add 9+6+9 is will give you 24 than you would times that by 6. So 9+6+9= 24 next 24×6=144.

6 0

3 years ago

Read 2 more answers

In a G.P the difference between the 1st and 5th term is 150, and the difference between the

liubo4ka [24]

Answer:

Either $\displaystyle \frac{-1522}{\sqrt{41}}$ (approximately $-238$ ) or $\displaystyle \frac{1522}{\sqrt{41}}$ (approximately $238$ .)

Step-by-step explanation:

Let $a$ denote the first term of this geometric series, and let $r$ denote the common ratio of this geometric series.

The first five terms of this series would be:

$a$ ,
$a\cdot r$ ,
$a \cdot r^2$ ,
$a \cdot r^3$ ,
$a \cdot r^4$ .

First equation:

$a\, r^4 - a = 150$ .

Second equation:

$a\, r^3 - a\, r = 48$ .

Rewrite and simplify the first equation.

$\begin{aligned}& a\, r^4 - a \\ &= a\, \left(r^4 - 1\right)\\ &= a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) \end{aligned}$ .

Therefore, the first equation becomes:

$a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) = 150$ ..

Similarly, rewrite and simplify the second equation:

$\begin{aligned}&a\, r^3 - a\, r\\ &= a\, \left( r^3 - r\right) \\ &= a\, r\, \left(r^2 - 1\right) \end{aligned}$ .

Therefore, the second equation becomes:

$a\, r\, \left(r^2 - 1\right) = 48$ .

Take the quotient between these two equations:

$\begin{aligned}\frac{a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right)}{a\cdot r\, \left(r^2 - 1\right)} = \frac{150}{48}\end{aligned}$ .

Simplify and solve for $r$ :

$\displaystyle \frac{r^2+ 1}{r} = \frac{25}{8}$ .

$8\, r^2 - 25\, r + 8 = 0$ .

Either $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ or $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ .

Assume that $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = -\frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= -\frac{1522\sqrt{41}}{41} \approx -238\end{aligned}$ .

Similarly, assume that $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = \frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= \frac{1522\sqrt{41}}{41} \approx 238\end{aligned}$ .

4 0

3 years ago