Lorraine writes the equation shown. x squared + y minus 15 = 0 She wants to describe the equation using the term relation and th
2 answers:
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Alright! Given that C(x) is Cost(Students) = 558, we can eliminate:
2. 558 students paid to attend the event.
5. The event generated $124 from student revenue.
Now, in order to find the cost per student we simply divide 124 on both sides:
124 cancels on the left and 558/124 is 4.5 or $4.50.
Since we just determined the cost of one student, we can eliminate 3.
To check if 124 students paid, we simply add the cost to the equation and check:
4.5(124) = 558
558 = 558 √
It checks out, so we determined that both 1 and 4 are correct.
2. 558 students paid to attend the event.
5. The event generated $124 from student revenue.
Now, in order to find the cost per student we simply divide 124 on both sides:
124 cancels on the left and 558/124 is 4.5 or $4.50.
Since we just determined the cost of one student, we can eliminate 3.
To check if 124 students paid, we simply add the cost to the equation and check:
4.5(124) = 558
558 = 558 √
It checks out, so we determined that both 1 and 4 are correct.