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Whitepunk [10]
3 years ago
10

(24 oz is $3.49, 48 oz is $6.49) Figure out the unit rate for each jar of pasta sauce.

Mathematics
1 answer:
Svet_ta [14]3 years ago
5 0

Answer:

Step-by-step explanation:

3.48/24= 14.54 cents/ oz

6.49/48= 13.52 cents/oz

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The prices of 3 different bags of dog food are given. Which size bag has the
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Bag 3!

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What is the mean of the data?
Law Incorporation [45]

Answer: B, 5.5

Step-by-step explanation:

4+4+4+5+5+6+6+6+6+9=55

55/10=5.5

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The following are the temperatures of 10 days in winter in °C. − 3 , 0 , 10 , 2 , 8 , − 5 , − 1 , 9 , 2 , − 3 Work out the mean
marissa [1.9K]

The mean temperature of the given data − 3 , 0 , 10 , 2 , 8 , − 5 , − 1 , 9 , 2 , − 3 is 1.9

mean= 1.9

<h3>What is mean of the data?</h3>

The mean, or average, is calculated by adding up the data and dividing by total number of data.

Given data: − 3 , 0 , 10 , 2 , 8 , − 5 , − 1 , 9 , 2 , − 3

Now, mean =   \frac{sum \;of\; observation}{Total \;number \;of \;observation}

mean = \frac{(-3)+ 0+10+2+8+(-5)+ (-1)+ 9+2+(-3)}{10}

           = \frac{19}{10}

mean= 1.9

Hence, the mean of − 3 , 0 , 10 , 2 , 8 , − 5 , − 1 , 9 , 2 , − 3  is 1.9

Learn more about mean here:

brainly.com/question/22871228

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3 0
2 years ago
Which form of money carries a value of its own, but is not equivalent to actual gold or silver?
masha68 [24]

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U.S. Currency

Step-by-step explanation:

6 0
3 years ago
The amount A of the radioactive element radium in a sample decays at a rate proportional to the amount of radium present. Given
slavikrds [6]

Answer:

a) \frac{dm}{dt} = -k\cdot m, b) m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }, c) m(t) = 10\cdot e^{-\frac{t}{2438.155} }, d) m(300) \approx 8.842\,g

Step-by-step explanation:

a) Let assume an initial mass m decaying at a constant rate k throughout time, the differential equation is:

\frac{dm}{dt} = -k\cdot m

b) The general solution is found after separating variables and integrating each sides:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }

Where \tau is the time constant and k = \frac{1}{\tau}

c) The time constant is:

\tau = \frac{1690\,yr}{\ln 2}

\tau = 2438.155\,yr

The particular solution of the differential equation is:

m(t) = 10\cdot e^{-\frac{t}{2438.155} }

d) The amount of radium after 300 years is:

m(300) \approx 8.842\,g

4 0
3 years ago
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