Well, we do not know how many fish Rita has, so lets represent that with y. Anyway, it says that catherine has twice as many fish as Rita. So that will be 2y. And Stella has twice as many as catherine, so that will be 2 x 2y. And that will be 4y. So Ruth has y, catherine has 2y and stella has 4y. And the total is 70. So that means that the number of fishes added together will be 70. That can be represented as;
y + 2y + 4y = 70
y is the same as 1y. And when you add y + 2y + 4y, you will get 7y. So
7y=70
Divide the both sides by 7. That will be;
y= 7 . So Rita has 7 fishes. Hope i helped.
Answer:
x=8
Step-by-step explanation:
Because you are solving for x, you want to cancel out the y terms. You can do this by multiplying the entire equations by numbers that will make the y terms have equal numbers but opposite signs.
2(2x-5y=1)
5(-3x+2y=-18)
This turns into
4x-10y=2
-15x+10y=-90
The y terms cancel out, and the other terms can be added together.
-11x=-88
x=8
Answer:
The expression that represents the number of deer in the forest is
y(x) = 50*(1.013)^x
Step-by-step explanation:
Assuming that the number of deer is "y" and the number of months is "x", then after the first month the number of deer is:
y(1) = 50*(1+ 0.15/12) = 50*(1.0125) = 50.625
y(2) = y(1)*(1.0125) = y(0)*(1.0125)² =51.258
y(3) = y(2)*(1.0125) = y(0)*(1.0125)³ = 51.898
This keeps going as the time goes on, so we can model this growth with the equation:
y(x) = 50*(1 - 0.15/12)^(x)
y(x) = 50*(1.013)^x
3.745 kilograms, because 1 gram =.01 kilograms
Answer: B. 8/100
Let's give 5/10 a denominator of 100 since 58/100 does, so they have common denominators:
5/10 * 10 = 50/100
Now, we can subtract 50/100 from 58/100 to find the unknown fraction:
58/100 - 50/100 = 8/100
This gives us an answer of,
B. 8/100
