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Zielflug [23.3K]
3 years ago
6

Find tan–11.4826 to the nearest degree.

Mathematics
2 answers:
Lelu [443]3 years ago
8 0

Answer:

2 deg

Step-by-step explanation:

adell [148]3 years ago
8 0

Answer:

11

Step-by-step explanation:

nearest is rounding and the nearest number is 4 and 4 keeps it the same

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Find the midpoint of the segment with the given endpoints. D(1, 2) and E(5, –2)
andre [41]
The formula is (x + x / 2, y + y / 2)
1 + 5 / 2 = 3
-2+2 / 2 = 0

the mid point is (3,0)
4 0
3 years ago
The Falcons’ third play went for +3 1/4 yards. Terrence thinks they lost yards, but his friend Ted thinks they gained yards. Who
Alexxandr [17]

Answer:

ted is right they gained yards

Step-by-step explanation:

becuase where it says +3 1/4 the + is the clue

7 0
2 years ago
Suppose x is any positive number.
ValentinkaMS [17]
<span>B: Circle 1 is a dilation of circle 2 with a scale factor of 4. 
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7 0
3 years ago
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The percentage of married couples who own a single family home is 33% for a given population. A financial analyst is interested
erik [133]

Answer:

For samples of size n=200, the standard error is of 0.033.

For samples of size n=300, the standard error is of 0.027.

For samples of size n=400, the standard error is of 0.024.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

The percentage of married couples who own a single family home is 33% for a given population.

This means that p = 0.33

Samples of 200:

s = \sqrt{\frac{0.33*0.67}{200}} = 0.033

For samples of size n=200, the standard error is of 0.033.

Samples of 300:

s = \sqrt{\frac{0.33*0.67}{300}} = 0.027

For samples of size n=300, the standard error is of 0.027.

Samples of 400:

s = \sqrt{\frac{0.33*0.67}{400}} = 0.024

For samples of size n=400, the standard error is of 0.024.

7 0
3 years ago
Find all values of c such that c/(c - 5) = 4/(c - 4). If you find more than one solution, then list the solutions you find separ
Deffense [45]

Answer:

\large\boxed{\bold{NO\ REAL\ SOLUTIONS}}\\\boxed{x=4-2i,\ x=4+2i}

Step-by-step explanation:

Domain:\\c-4\neq0\ \wedge\ c-5\neq0\Rightarrow c\neq4\ \wedge\ c\neq5\\\\\dfrac{c}{c-5}=\dfrac{4}{c-4}\qquad\text{cross multiply}\\\\c(c-4)=4(c-5)\qquad\text{use the distributive property}\\\\c^2-4c=4c-20\qquad\text{subtract}\ 4c\ \text{from both sides}\\\\c^2-8c=-20\qquad\text{add 20 to both sides}\\\\c^2-8c+20=0\qquad\text{use the quadratic formula}

\text{for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

x^2-8x+20=0\\\\a=1,\ b=-8,\ c=20\\\\b^2-4ac=(-8)^2-4(1)(20)=64-80=-16

\text{In the set of complex numbers:}\\\\i=\sqrt{-1}\\\\\text{therefore}\ \sqrt{b^2-4ac}=\sqrt{-16}=\sqrt{(16)(-1)}=\sqrt{16}\cdot\sqrt{-1}=4i\\\\x=\dfrac{-(-8)\pm4i}{2(1)}=\dfrac{8\pm4i}{2}=\dfrac{8}{2}\pm\dfrac{4i}{2}=4\pm2i

6 0
3 years ago
Read 2 more answers
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