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Murljashka [212]
3 years ago
6

The top of the desk is shaped like a trapezoid the bases of the trapezoid are 26.5 and 30 cm long the area of the desk is 791 CM

the height of a trapezoid is the width of the desk right and solve an equation to find the width of the desk
Mathematics
1 answer:
kotegsom [21]3 years ago
5 0

Answer:

28 cm

Step-by-step explanation:

Given that :

Area = 791 cm

Base, b1 = 26.5 cm

Base, b2 = 30 cm

Area, A of trapezoid :

A = 1/2 (a + b) h

Where a and b are the bases ;

791 = 1/2(26.5 + 30)h

791 = 0.5(56.5)h

791 = 28.25h

h = 791 / 28.25

h = 28 cm

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Given:
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Given h(x) = -5x + 3, find h(5).
cluponka [151]

Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

h(x) = -5x + 3

h(5) is x = 5

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em> [Function]:                                                                                h(5) = -5(5) + 3
  2. Multiply:                                                                                                             h(5) = -25 + 3
  3. Add:                                                                                                                   h(5) = -22
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~\hfill ST=\sqrt{( -12)^2 + ( -5)^2}\implies \boxed{ST=13} \\\\\\ T(\stackrel{x_1}{5}~,~\stackrel{y_1}{0})\qquad R(\stackrel{x_2}{-7}~,~\stackrel{y_2}{5}) ~\hfill TR=\sqrt{(~~ -7- 5~~)^2 + (~~ 5- 0~~)^2} \\\\\\ ~\hfill TR=\sqrt{( -12)^2 + (5)^2}\implies \boxed{TR=13} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{\LARGE perimeter}}{24~~ + ~~13~~ + ~~13\implies \text{\LARGE 50}}~\hfill

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Step-by-step explanation:

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