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Sindrei [870]
3 years ago
8

si franco comió 8/3 de pizza y Fabián comió 5/6 de la misma pizza. ¿quien comió más ? si quedó 4/9 de pizza.​

Mathematics
1 answer:
devlian [24]3 years ago
8 0

Answer:

Franco comió 8/3 de pizza.

Fabián comió 5/6 de pizza.

Queremos saber quien comió más.

Entonces básicamente queremos ver cuál número es más grande, 8/3 o 5/6,

Podemos reescribir el primero como:

8/3 = (2 + 3 + 3)/3 = 2/3 + 3/3 + 3/3 = 2/3 + 1 + 1

      = 2 + 2/3

En cambio, para el número 5/6, el numerador es menor que el denominador, entonces sabemos que:

5/6  < 1

Claramente podemos ver que 8/3 > 5/6

Entonces podemos concluir que Franco comió más.

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x=25,y=15 Not to sure abt this answer but I think I got it

7 0
3 years ago
Brainlest for answered
Helen [10]

Answer:

Hello! answer: 4/5

Step-by-step explanation:

20 ÷ 5 = 4 25 ÷ 5 = 5 that is 4/5 therefore 4/5 is the answer because we cannot reduce any further HOPE THAT HELPS!

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3 years ago
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Police estimate that​ 25% of drivers drive without their seat belts. If they stop 6 drivers at​ random, find the probability tha
Furkat [3]

Answer:

17.80% probability that all of them are wearing their seat belts.

Step-by-step explanation:

For each driver stopped, there are only two possible outcomes. Either they are wearing their seatbelts, or they are not. The drivers are chosen at random, which mean that the probability of a driver wearing their seatbelts is independent from other drivers. So we use the normal probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

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In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Police estimate that​ 25% of drivers drive without their seat belts.

This means that 75% wear their seatbelts, so p = 0.75

If they stop 6 drivers at​ random, find the probability that all of them are wearing their seat belts.

This is P(X = 6).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{6,6}.(0.75)^{6}.(0.25)^{0} = 0.1780

17.80% probability that all of them are wearing their seat belts.

3 0
3 years ago
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For a left-tailed test, the critical value of z so that a hypothesis test would reject the null hypothesis at 1% significance le
mars1129 [50]

Answer:

C.-2.33

Step-by-step explanation:

We are given that

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We have to find  the critical value of z  for a left-tailed test.

To find the critical value , we will use the z-table at significance level 0.01 for left-tailed test.

By using the z-table at significance level 0.01 for left-tailed test

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We get p-value by using z-critical value

P-value=0.0099<0.01

So, hypothesis  test would be reject the null hypothesis at  at 1% significance level.

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8 0
3 years ago
What is the solution for 1/2+x=5/4
prohojiy [21]
<span>1/2-(5/4) = x+1/4 // - x+1/4

1/2-x-(5/4)-(1/4) = 0

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</span>
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