If the coefient in front of the squared term is positive, it opens to the right or up
if it is in front of x^2, it opens up
if it is in front of y^2, it opens right
opens to the right
Answer:
h(t) = -16t2 + 186t + 43
at the ground h = 0
hence; -16t2 + 186t + 43 = 0
solving this quadratic equation using the quadratic formula ; a = -16, b = 186, c = 43 ; x = (-b +-(b2 - 4ac)1/2)/2a
gives t = 11.8 seconds to the nearest tenth (note that the negative root has no practical significance)
Step-by-step explanation:
Answer:
Step-by-step explanation:
first multiply 1 with 2+5i then multiply 2i with 2+5i and you will get
2+5i+4i+10i^2
then in the next step add 4i and 5i you will get 9i
in the next step put i^2=-1 and you will get -10
in the last step just substract 2-10 you will get -8 and 9i
and your answer will be -8+9i
