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Anni [7]
3 years ago
7

How many money did juwad earn in the first week

Mathematics
1 answer:
4vir4ik [10]3 years ago
5 0

Answer:

no pic or nothing but here is a number 324

Step-by-step explanation:

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PLEASE HELP?
const2013 [10]

Answer:

When we have a function g(x)

We will have a maximum at x when:

g'(x) = 0

g''(x) < 0.

Now we start with:

g(x) = 3*x^4 - 8*x^3

The first derivation is:

g'(x) = 4*3*x^3 - 3*8*x^2

g'(x) = 12*x^3 - 24*x^2

We can rewrite this as:

g'(x) = x^2*(12*x - 24)

Now we want to solve:

g'(x) = 0 =  x^2*(12*x - 24)

We have one trivial solution, that is when x = 0.

The other solution will be when the term inside of the parentheses is equal to zero.

Then we need to solve:

12*x - 24 = 0

12*x = 24

x = 24/12 = 2

Then g'(x) is equal to zero for x = 0, and x = 2.

Notice that both of these points are included in the interval [ -2,2 ]

Now we need to look at the second derivative of g(x):

g''(x) = 3*12*x^2 - 2*24*x

g''(x) = 36*x^2 - 48*x

Ok, now we need to evaluate this in the two roots we found before:

if x = 0:

g''(0) = 36*0^2 - 48*0 = 0

g''(0) = 0

Then we do not have a maximum at x = 0, this is a point of inflection.

if x = 2:

g''(2) = 36*(2^2) - 48*2 = 48

then:

g''(2) > 0

This is an absolute minimum.

Now let's look only at the interval [ -2,2 ]

We know that:

g''(0) =  0

g''(2) > 0

Then at some point, we should have g''(x) < 0 in our interval.

We need to find the first point such that happens, so let's try with the lower limit of the interval but with the first derivation, if g'(x) < 0, this means that the function is decreasing from that point on, then that point will be a maximum in our interval.

x = -2

g'(-2) = (-2)^2*(12*-2 - 24) = -192

And if we look at the function:

g'(x) = x^2*(12*x - 24)

We can easily see that it is negative unitl x = 0, and then it keeps being negative until x = 2.

So in the interval  [ -2,2 ], the function g'(x) is always negative or zero, this means that in the interval  [ -2,2 ], the function g(x) is always decreasing or constant.

Then the absolute maximum of g(x) in the interval  [ -2,2 ]  will be  x = -2

this means that:

g(-2) ≥ g(x) for all x ∈  [ -2,2 ]

6 0
2 years ago
Lady Gaga bought a package of pens for $2.25 and some pencils that cost $.30 each she paid a total of $4.65 for these items befo
Alexxx [7]

Answer:

y=mx+b is the final answer!

Step-by-step explanation:

i used a calculator so i am 100% sure these are right.

7 0
3 years ago
Identify the oblique asymptote of f(x) = quantity x plus 4 over quantity 3 x squared plus 5 x minus 2.
faltersainse [42]
f(x) = \frac{x + 4}{3x^{2} + 5x - 2}

                     3x² + 5x - 2 = 0
                3x² + 6x - x - 2 = 0
3x(x) + 3x(2) - 1(x) - 1(2) = 0
          3x(x + 2) - 1(x + 2) = 0
                  (3x - 1)(x + 2) = 0
3x - 1 = 0       or       x + 2 = 0
    + 1 + 1                     - 2  - 2 
     3x = 1          or          x = -2
      3     3                       1     1
       x = ¹/₃         or         x = -2

      f(x) = 3x² + 5x - 2
     f(¹/₃) = 3(¹/₃)² + 5(¹/₃) - 2
     f(¹/₃) = 3(¹/₉) + 1²/₃ - 2
     f(¹/₃) = ¹/₃ - ¹/₃
     f(¹/₃) = 0
(x, f(x)) = (¹/₃, 0)

      f(x) = 3x² + 5x - 2
     f(-2) = 3(-2)² + 5(-2) - 2
     f(-2) = 3(4) - 10 - 2
     f(-2) = 12 - 12
     f(-2) = 0
(x, f(x)) = (-2, 0)

    Vertical Asymptotes: ¹/₃ or -2
Horizontal Asymptotes: 0
      Oblique Asymptote: No Asymptotes
3 0
3 years ago
Read 2 more answers
Please help, much appreciated!!!! (will mark brainliest)
Jobisdone [24]

Answer:

16 years

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
What is the length of this line?<br><br><br> Please help me! Thank you! ☺️
Semmy [17]

Answer:

A

Step-by-step explanation:

7 0
3 years ago
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