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3 years ago

5

Please please please help

1 answer:

Elina [12.6K]3 years ago

4 0

Median of (72 82 92 93 94 97 98 102)
Median: 93.5
MAD : 7.125

Median of ( 53 59 64 65 65 66 67 69)
Median : 65
MAD : 3.75

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Find the equation of a line parallel to y=-10x-5 passing through the coordinate (-3,5)

Allushta [10]

With a given parallel line and a given point on the line
we can use the point-line method: y-y0=m(x-x0)
where
y=mx+k is the given line, and
(x0,y0) is the given point.

Here
m=-10, k=-5, (x0,y0)=(-3,5)

=> the required line L is given by:
L: y-5=-10(x-(-3))

on simplification
L: y=-10x-30+5
L: y=-10x-25

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3 years ago

The net of a solid figure is shown below: Four squares are shown side by side in a row. The second square has a square above it

Elis [28]

There are 6 squares so u multiply 6x3=18 is the total surface area

8 0

3 years ago

17) Find the slope of the line that passes through each pair of points.

elena55 [62]

Its c because i did it already and got it right

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2 years ago

A cone and its dimensions are shown in the diagram. What is the volume of the cone in cubic inches?

Vinvika [58]

Answer:

The exact value of the volume is equal to

$V=19\frac{397}{512}\pi\ in^{3}$

Step-by-step explanation:

we know that

The volume of a cone is equal to

$V=\frac{1}{3}\pi r^{2} h$

we have

$D=5\frac{5}{8}\ in$

convert to an improper fraction

$D=5\frac{5}{8}\ in=\frac{5*8+5}{8}=\frac{45}{8}\ in$

$r=(45/8)/2=\frac{45}{16}\ in$

$h=7\frac{1}{2}\ in=\frac{7*2+1}{2}=\frac{15}{2}\ in$

substitute in the formula of volume

$V=\frac{1}{3}\pi (\frac{45}{16}^{2})(\frac{15}{2})=\frac{30,375}{1,536}\pi\ in^{3}$

Simplify

$\frac{30,375}{1,536}=\frac{29,184}{1,536}+\frac{1,191}{1,536}=19\frac{397}{512}$

substitute

$V=19\frac{397}{512}\pi\ in^{3}$

4 0

3 years ago

A rectangular swimming pool measures 50 meters in length and 25 meters in width. If the length in the scale drawing is 10 cm, wh

mash [69]

Answer:

The 25 m width of the actual swimming pool in the scale drawing is 5 cm

Step-by-step explanation:

The dimensions of the actual swimming pool given are

Length = 50 meters

Width = 25 meters

The length of the swimming pool on the scale drawing = 10 cm

The scale of the scale drawing is therefore;

10 cm on the scale drawing is equivalent to 50 meters of the actual swimming pool

Which gives;

10 cm:50 m

However, 50 m = 5,000 cm, therefore;

10 cm:5,000 cm or 10 : 5,000

Which is 10 to 5000 or 10/10 to 5000/10 = 1 to 500

The scale of the scale drawing is 1 to 500

or 1 cm of the scale drawing = 5 meters of the actual swimming pool

Therefore, the width of 25 meters of the actual swimming pool can be given as follows;

5 m = 1 cm

1 m = 1 cm/5

25 m = 25× 1 m = 25 × 1 cm/5 = 5 cm

Therefore, the 25 m width of the actual swimming pool in the scale drawing = 5 cm.

5 0

3 years ago