Answer: By moving from sea level to Mexico City air pressure is reduced by 25%.
Step-by-step explanation:
Hi, to answer this we have to apply a decrease rate formula
P0 (1-r)^x
Where:
p0= initial pressure
r = decrease rate. (0.4 = 0.4/100=0.004 decimal form)
x = feet (hundredths, since the air pressure decays every 100 feet we have to divide the input value by 100)
Replacing with the values given
P0 (1- 0.4/100)^(7340/100) =
P0 (0.996)^73.4 =
P0 ( 0.75)=
The air pressure at Mexico City compared to the sea level is 75% (0.75 x 100 =75%)
To obtain the percent decrease
100% -75% =25%
Speed = 416 miles / 8hrs = 52 miles per hr.
Distance = Speed * Time = 52 * 22 = 1144miles
The little square means 90° and a straight line means 180° so 180 minus 68° minus 90° is 22° which leaves,
1) 112° and since you can flip 68° exacly the same on both sides it is a vertical angle which means
3)68.
4) 90°
Just inverse the fraction and you will find the reciprocal:
The reciprocal of 15/7 is 7/15
The reciprocal of 7/12 is 12/7
