Ask question

Ask question

All categories

2 years ago

7

On a horizontal number line, numbers to the...... are less than numbers to the..... Numbers to the right are........ numbers to

the left.

1 answer:

Neko [114]2 years ago

8 0

on a horizontal number line . numbers to the left are less than numbers to the right .. numbers to the right are less than numbers to the left

You might be interested in

Which algebraic expressions are polynomials

ivolga24 [154]

Answer:

2,3,5,6

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Y = 2 - 4x input output

tester [92]

Every function is a rule which tells you how to associate inputs and outputs. The input, also known as independent variable, is often indicated with the letter $x$ , while the output, also known as dependent variable, is often indicated with the letter $y$ .

With this notation, we write $y = f(x)$ , read "y is a function of x", in the sense that the value of the variable y depends on the value of the variable x, and f is the function that tells you how y depends on x.

In your example, you have $y = f(x) = 2-4x$ , which means "subtract four times the input (4x) from 2"

So, it doesn't matter which input you chose (i.e. the value for x), because you will always have to behave this way:

Pick an input value, x
Multiply it by four to get 4x
Subtract this number from 2: 2-4x

Here are some examples of explicit calculations: if I choose $x = 2$ and input, the workflow will be

Pick an input value, 2
Multiply it by four to get 8
Subtract this number from 2: 2-8=-6

So, if the input is 2, the output is -6

Similarly, if we choose $x = 0$ as input, we have:

Pick an input value, 0
Multiply it by four to get 0
Subtract this number from 2: 2-0=2

So, if the input is 0, the output is 2. And so on: for every possible value for x you have the correspondant value for y, with the function f telling you how to associate one with the other.

4 0

2 years ago

A lifeguard is in a look out chair and sees a person in distress. The eye level of the lifeguard is 15 feet above the ground. Th

faltersainse [42]

Answer:

Horizontal distance between lifeguard and the person is 22 feet.

Step-by-step explanation:

Given: A lifeguard sees a person in distress.The eye level of the lifeguard is 15 feet above the ground. Angle of depression is 34°.

To find: Horizontal distance between lifeguard and the person.

Solution : If we draw a triangle then tan∅ = $\frac{height}{base}$

Here base is the horizontal distance.

Now we put the values in the formula.

tan 34° = $\frac{15}{base}$

Or Base = $\frac{15}{tan34}$

= $\frac{15}{0.675} = 22.22 feet$

So the answer is 22 feet.

7 0

2 years ago

Find the missing value. Show your work<br> (GEOMETRY, PLEASE HELP!!)

sammy [17]

Sin51=y/12

y=12sin51 units

y≈9.33 units (to nearest hundredth of a unit)

...

tanα=12/5

α=arctan2.4°

α≈67.38° (to nearest hundredth of a degree)

...

tan13=x/24

x=24tan13 units

x≈5.54 units (to nearest hundredth of a unit)

...

sin20=10/x

x=10/sin20 units

x≈29.24 units (to nearest hundredth of a unit)

3 0

2 years ago

Find the derivative of

kirill [66]

Answer:

$\displaystyle y'(1, \frac{3}{2}) = -3$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Algebra I</u>

Coordinates (x, y)
Functions
Function Notation
Terms/Coefficients
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

<u>Calculus</u>

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

<u>Step 1: Define</u>

<u /> $\displaystyle y = \frac{3}{2x^2}$ <u />

$\displaystyle \text{Point} \ (1, \frac{3}{2})$

<u>Step 2: Differentiate</u>

[Function] Rewrite [Exponential Rule - Rewrite]: $\displaystyle y = \frac{3}{2}x^{-2}$
Basic Power Rule: $\displaystyle y' = -2 \cdot \frac{3}{2}x^{-2 - 1}$
Simplify: $\displaystyle y' = -3x^{-3}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{-3}{x^3}$

<u>Step 3: Solve</u>

Substitute in coordinate [Derivative]: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1^3}$
Evaluate exponents: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1}$
Divide: $\displaystyle y'(1, \frac{3}{2}) = -3$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

6 0

2 years ago