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laiz [17]
3 years ago
5

What is the solution of the equation √3x+2=√2x-2

Mathematics
1 answer:
MakcuM [25]3 years ago
7 0

Step-by-step explanation:

\sqrt{3 x -  \sqrt{2x = 4} }

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Total blood cholesterol level was measured for each of
laiz [17]
<h3>Answer: Mean = 218.9.</h3><h3>Median = 229</h3><h3>Mode = Zero mode.</h3>

Step-by-step explanation:

Given blood cholesterol level was measured for each of 8 adults (in mg/dL) are:

264, 191, 160, 148, 262, 212, 268, 246

In order to find the mean, we need to add all those 8 numbers and divide by 8.

Therefore, mean = \frac{264+191+160+148+262+212+268+246}{8} =\frac{1751}{8} =218.9.

<h3>Mean = 218.9.</h3>

In order to find the median, we need to arrange them in ascending order:

148, 160, 191, 212, 246, 262, 264, 268.

The middle most two values are 212 and  246.

Therefore, median = \frac{212+246}{2} =\frac{458}{2} = 229.

<h3>Median = 229.</h3>

\mathrm{The\:mode\:is\:the\:term\:in\:the\:data\:set\:that\:appears\:the\:most.}

\mathrm{If\:there\:is\:more\:than\:one\:term\:that\:appears\:the\:most,\:then\:there\:is\:no\:mode.}

\mathrm{Count\:the\:number\:of\:times\:each\:element\:appears\:in\:the\:list}

\begin{pmatrix}148&160&191&212&246&262&264&268\\ 1&1&1&1&1&1&1&1\end{pmatrix}

\mathrm{The\:most\:common\:element\:is\:not\:unique,\:so\:there\:is\:no\:mode}

<h3>Therefore, Mode = Zero mode.</h3>
5 0
4 years ago
Last week Alexandra was paid $56 for 7 hours of work. How much money does Alexandra's pay per hour?
Pie
The answer would be $8 per hour
6 0
4 years ago
Read 2 more answers
If (x + 2) is a factor of x3 − 6x2 + kx + 10, k
kherson [118]

Answer:

k = -11

Step-by-step explanation:

Let p(x) = x^3-6x^2+kx+10

And x+2 is a factor of p(x)

Let x+2 = 0 => x = -2

Putting in p(x)

=> p(-2) = (-2)^3-6(-2)^2+k(-2)+10

<u><em>By remainder theorem, Remainder will be zero</em></u>

=> 0 = -8-6(4)-2k+10

=> 0 = -8-24+10-2k

=> 0 = -22-2k

=> -2k = 22

Dividing both sides by -2

=> k = -11

4 0
3 years ago
Read 2 more answers
Obtain or compute the following quantities.
iVinArrow [24]

Answer:

a) F_{0.05,4,7}=0.16

b) F_{0.05,7,4}=0.24

c) F_{0.95,4,7}=4.12

d) F_{0.95,7,4}=6.09

e) F_{0.99,8,12}=4.50

f) F_{0.01,8,12}=0.18

g) P(F_{5,4} \leq 6.26)=0.95

h) P(0.177 \leq F_{10,5} \leq 4.74)=0.94

Step-by-step explanation:

(a) F0.05, 4, 7 (Round your answer to two decimal places.)

For this case we need a valueof the F distribution with 4 degrees of freedom for the numerator and 7 for the denominator that accumulates 0.05 of the area on the left tail. We can use the following excel code: "=F.INV(0.05,4,7)". And we got:

F_{0.05,4,7}=0.16

(b) F0.05, 7, 4 (Round your answer to two decimal places.)

For this case we need a valueof the F distribution with 7 degrees of freedom for the numerator and 4 for the denominator that accumulates 0.05 of the area on the left tail. We can use the following excel code: "=F.INV(0.05,7,4)". And we got:

F_{0.05,7,4}=0.24

(c) F0.95, 4, 7 (Round your answer to three decimal places.)

For this case we need a valueof the F distribution with 4 degrees of freedom for the numerator and 7 for the denominator that accumulates 0.95 of the area on the left tail. We can use the following excel code: "=F.INV(0.95,4,7)". And we got:

F_{0.95,4,7}=4.12

(d) F0.95, 7, 4 (Round your answer to three decimal places.)

For this case we need a valueof the F distribution with 7 degrees of freedom for the numerator and 4 for the denominator that accumulates 0.95 of the area on the left tail. We can use the following excel code: "=F.INV(0.95,7,4)". And we got:

F_{0.95,7,4}=6.09

(e) the 99th percentile of the F distribution with v1 = 8, v2 = 12 (Round your answer to two decimal places.)

So for this case we need a value on the F distribution with 8 degrees of freedom for the numerator and 12 for the denominator that accumulates 0.99 of the area on the left tail. And we can use the following excel code: "=F.INV(0.99,8,12)". And we got:

F_{0.99,8,12}=4.50

(f) the 1st percentile of the F distribution with v1 = 8, v2 = 12 (Round your answer to three decimal places.)

So for this case we need a value on the F distribution with 8 degrees of freedom for the numerator and 12 for the denominator that accumulates 0.01 of the area on the left tail. And we can use the following excel code: "=F.INV(0.01,8,12)". And we got:

F_{0.01,8,12}=0.18

(g) P(F ≤ 6.26) for v1 = 5, v2 = 4 (Round your answer to two decimal places.)

For this case we want to find the probability that the F distribution with 5 degrees on the numerator and 4 on the denominator would be less or equal than 6.26. We can use the following excel code: "=F.DIST(6.26,5,4,TRUE)". And we got

P(F_{5,4} \leq 6.26)=0.95

(h) P(0.177 ≤ F ≤ 4.74) for v1 = 10, v2 = 5 (Round your answer to two decimal places.)

For this case we want to find the probability that the F distribution with 10 degrees on the numerator and 5 on the denominator would be between 0.177 and 4.74. We can use the following excel code: "=F.DIST(4.74,10,5,TRUE)-F.DIST(0.177,10,5,TRUE)". And we got

P(0.177 \leq F_{10,5} \leq 4.74)=0.94

3 0
3 years ago
Read 2 more answers
Rewrite 10^32 x 10^6 using a single exponent
Zarrin [17]

10^38

<u>Step-by-step explanation:</u>

Given that,

10^32 x 10^6

Here the base is same (10) and the powers are 32 and 6.

These 2 bases are in multiplication form so the powers can be added up.

10^32 x 10^6 = 10^(32+6)

= 10^38

4 0
4 years ago
Read 2 more answers
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