21−=2(2−)=2cos(−1)+2 sin(−1)
−1+2=−1(2)=−1(cos2+sin2)=cos2+ sin2
Is the above the correct way to write 21− and −1+2 in the form +? I wasn't sure if I could change Euler's formula to =cos()+sin(), where is a constant.
complex-numbers
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edited Mar 6 '17 at 4:38
Richard Ambler
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asked Mar 6 '17 at 3:34
14wml
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1 Answer
1
No. It is not true that =cos()+sin(). Notice that
1=1≠cos()+sin(),
for example consider this at =0.
As a hint for figuring this out, notice that
+=ln(+)
then recall your rules for logarithms to get this to the form (+)ln().
Answer:
x = 4
Step-by-step explanation:
y = - 2 is the equation of a horizontal line parallel to the x- axis.
A perpendicular line is therefore a vertical line parallel to the y- axis with equation
x = c
where c is the value of the x- coordinates the line passes through.
The line passes through (4, - 2 ) with x- coordinate 4 , thus
x = 4 ← equation of perpendicular line
Answer:
Step-by-step explanation:
Let x be the percentage then...
Start by dividing both sides by 4:
Simplify the fraction:
Then, multiply the fraction by 50/50, so we can get a number over 100 (that number would be the percentage). Note we can only multiply it by 50/50 since it is essentially multiplying the fraction by 1.
We know that y=7x, so we just need tu put it into the 1st equation
So we found x. Now we can find y
Answer:
x=1, y=7; or (1;7)
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