Answer:
m<CDE=66 degrees.
Step-by-step explanation:
(1) Extend the segment DC so it intersects with line BA. Call the intersection F.
(2) Consider triangle BCF. In here, we are given m<ABC=24 deg. Since m<BCD = 90 deg, we known that m<BCF = 90 deg. Knowing two angles in the triangle BCF lets us determine the rhird angle m<BFC = 180-90-24 = 66 deg.
(3) Because of the fact that AB || DE and the fact that line DF intersects AB and DE, the angles <BFC and <CDE are congruent. Therefore m<CDE=66 deg.
Answer:
{5, 6, 7}
Step-by-step explanation:
When we have a given relation, the domain is the set of inputs, and the range as the set of the outputs.
so for a function f(x), and a domain {a. b. c}
The range is:
{f(a), f(b), f(c)}
In this case, we have:
f(x) = x + 6
and the domain is {-1, 0, 1}
Then the range is:
{ f(-1), f(0), f(1) }
{-1 + 6, 0 + 6, 1 + 6}
{5, 6, 7}
The correct option is the third one.
Note that the 2nd equation can be re-written as y=8x-10.
According to the second equation, y=x^2+12x+30.
Equate these two equations to eliminate y:
8x-10 = x^2+12x+30
Group all terms together on the right side. To do this, add -8x+10 to both sides. Then 0 = x^2 +4x +40. You must now solve this quadratic equation for x, if possible. I found that this equation has NO REAL SOLUTIONS, so we must conclude that the given system of equations has NO REAL SOLUTIONS.
If you have a graphing calculator, please graph 8x-10 and x^2+12x+30 on the same screen. You will see two separate graphs that do NOT intersect. This is another way in which to see / conclude that there is NO REAL SOLUTION to this system of equations.
Answer:
The value of x is 5.
The value of y is 4.
Step-by-step explanation:
From the figure, the lengths of the lines with equal number of markings are equal.
So, we will have the length of 7x - 4 = 31.
We solve for 'x'.
We get: 7x = 35
⇒ x = 5
Similarly, 4y + 8 = 24
⇒ 4y = 24 - 8
⇒ 4y = 16
⇒ y = 4
Therefore, the value of x = 5 and y = 4.
Hence, the answer.
Answer:
b
Step-by-step explanation:
8
