Step-by-step explanation:
We have,
A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function :
......(1)
Part (a) :
The maximum height reached by the ball is given by :
Part (b) :
The maximum height of the ball is calculated by putting t = 1.125 in equation (1) such that :
Answer:
(3 ± √23 * i) /4
Step-by-step explanation:
To solve this, we can apply the Quadratic Equation.
In an equation of form ax²+bx+c = 0, we can solve for x by applying the Quadratic Equation, or x = (-b ± √(b²-4ac))/(2a)
Matching up values, a is what's multiplied by x², b is what's multiplied by x, and c is the constant, so a = 2, b = -3, and c = 4
Plugging these values into our equation, we get
x = (-b ± √(b²-4ac))/(2a)
x = (-(-3) ± √(3²-4(2)(4)))/(2(2))
= (3 ± √(9-32))/4
= (3 ± √(-23))/4
= (3 ± √23 * i) /4
A, Is the answer according to my calculations.
Coral is sometimes used to replace human bone
