Formula:
Minimum = first element of set
First Quartile = (n+1)/4
Median = (n+1)/2
Third Quartile = 3(n+1)/4
Maximum = Last element of set.
Solution:<span>
The five number summary of ( 90, 85, 97, 76, 89, 58, 82, 102, 70, and 67) is,
Minimum = 58
First Quartile = 70
Median: = 83.5
Third Quartile = 90
Maximum = 102</span>
Our line equation is
where the slope m=1/2 and the y-intercept b is b=7.
Parallel lines has the same slope. Hence, their slope is always
in this case.
They would need 34.125 tons of rations.
In order to find this, we first need to see how many pounds of rations a single soldier eats in a week. To do this, we take the total eaten in 3 weeks and divide by 3. Then we divide by the number of soldiers.
16,380/3 weeks= 5460 lbs per week
5460/520 soldiers = 10.5 lbs per soldier per week
Now we look to see how many soldiers we will have in total after adding. There are 520 to start and we add 780 to get 1300 total. Next we multiply that by the total per soldier per week.
10.5lbs per soldier per week * 1300 soldiers = 13,650lbs per week
Then we have to multiply by the 5 weeks that battalion will be there.
13,650lbs * 5 weeks = 68,250lbs of rations or 24.125 tons.
<h3>Solution :</h3>
By cross multiply, we get
Therefore, answer is 
