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2 years ago

What is the area of the triangle?

Mathematics

1 answer:

liberstina [14]2 years ago

3 0

Answer:

Step-by-step explanation:

A = bh/2

A= 8 x 12 / 2

A= 96 / 2

A = 48

You might be interested in

What is 4x-9+19=8x-14

yawa3891 [41]

- 4x from 8x = 4x
-9 + 19 = 4x -14
-9 + 19 = 10
10 = 4x -14
+14
24 = 4x
divide by 4
X = 6

4 0

3 years ago

Molly opened a bank account. She deposited $86.50 into her account every month for 20 months. She used $24.50 every month to pay

anastassius [24]

She spent $310 on the singing camp.

MY WORK:

I multiplied $86.50*20 because $86.50 is the amount she deposited for 20 months. $86.50*20=$1740.00

Then I multiplied $24.50*20 because she spent $24.50 for 20 months. $24.50*20= $490.00

Then I subtracted $1740.00-$490.00 because she spent $490 out of her bank account. $1740.00-$490.00=$1240.00

Finally, because its 1/4 of her money, I divided $1240.00 by 4. $1240 divided by 4= $310

Hope this helps!!

8 0

3 years ago

What is (-2)+(-2)+(-2)??

Rama09 [41]

Answer:

-6

Step-by-step explanation:

hope this helps ;)

5 0

2 years ago

Read 2 more answers

If someone tells you your body temperature is 98.6°, what scale is being used? How do you know?

Alla [95]

Answer:

Fahrenheit

Step-by-step explanation:

When I am getting my temperature checked, it is usually checked in Fahrenheit, and my temperature is around 98.6 degrees.

6 0

3 years ago

Someone please be awesome and help me please :(

solong [7]

Answer:

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Step-by-step explanation:

$x^2+\frac{b}{a}x+\frac{c}{a}=0$

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared. Whatever you add in, you must take out.

$x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

Now we are read to write that one part (the first three terms together) as a square:

$(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

I don't see this but what happens if we find a common denominator for those 2 terms after the square. (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

$(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0$

They put it in ( )

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

I'm going to go ahead and combine those fractions now:

$(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0$

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

$(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0$

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

$x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}$

$x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}$

Now subtract b/(2a) on both sides:

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Combine the fractions (they have the same denominator):

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

6 0

3 years ago