Answer:
Step-by-step explanation:
First of all, the number before the decimal would be the whole number of the fraction.
So, 
Then, you would put 0.83 over a fraction.
So because you cannot simplify it anymore, it would be
Answer:
The correct answer is c = -8/3.
Step-by-step explanation:
The first step in solving this problem would be to simplify by combining like terms on the left side of the equation.
6c - 8 - 2c = -16 + c
4c - 8 = -16 + c
Then, we can subtract c from both sides of the equation to get rid of the positive c on the right side of the equation.
4c - c - 8 = -16 + c - c
3c - 8 = -16
Next, we can add 8 to both sides of the equation.
3c - 8 + 8 = -16 + 8
3c = - 8
Then, we can divide both sides of the equation by 3.
c = -8/3
Hope this helps!
Answer:
is in quadrant II
Step-by-step explanation:
Given
and 
Required
Where is
and imply that
is in quadrant II
Because that is only quadrant where and exist.
When you find the area, you want to break it up into different parts. Therefore, one part would be a square and the other part can be a trapezoid. Start out with finding the area of a square by multiplying 6 and 6. This will get you 36. Then, subtract 6 from 21. This will get you, 15. Then use the area of a trapezoid formula, which is A=(a+b)/2 times H. The H is the heigh, the a and b are the top and bottom bases. So if you plug it into the equation, (7+15)/2 then multiply that by 6 ( which is the height). this will get you 66. If you add 66+36, it equals 102 which is the area
Answer:
1,2,3 and 6 are similar triangles by AA similarity
Step-by-step explanation:
1) ∠DEC ≅ ∠FEG {Vertically opposite angles}
DC // GF
∠ECD ≅ ∠EGF {Alternate interior angles}
∠EDC ≅ ∠EFG {Alternate interior angles}
ΔDEC & ΔFEG are similar triangles by AA similarity
2)MN // QP
∠LQP ≅ ∠QMN {Corresponding angles }
∠LPQ ≅ ∠PNM {Corresponding angles}
ΔLQP & ΔLMN are similar triangles by AA similarity
3) In ΔSYE ,
∠S = 180 - 90 - 39
∠S = 51°
In ΔCHW,
∠H = 180 - 51 - 90
∠H = 39
ΔSYE and ΔCHW
∠S ≅ ∠W = 51°
∠Y ≅ ∠C = 90°
∠E ≅∠H = 39°
ΔSYE & ΔWCH are similar triangles by AA similarity
6) ∠P ≅ ∠Z {Given}
∠PXQ ≅∠ZXY {Vertically opposite angles}
ΔPXQ & ΔZXY are similar triangles by AA similarity
