Do you remember how to find the area of a circle ?
Big Fat Hint: The area of a circle is (pi) x (its radius)² .
Can you find the area of the big circle ... the one with radius = 18 m ?
Do that. The whole big circle, just as if there was nothing inside it, and
no shaded region.
I'll wait.
Now, can you find the area of the small circle ... the one with radius = 12 m ?
Do that.
I'll wait.
The area of the shaded region is just
(the area of the big circle) minus (the area of the small circle) !
I got 180 pi or roughly 565.2 m². I could be wrong. You should check it.
(3j, 3k) and (3/j, 3k)
So if their x values have the same signs and their y values have the same signs, they are in the same quadrant.
If j is negative, both 3j and 3/j would be negative. If j is positive then both 3j and 3/j are positive.
And 3k is the same as 3k.
Answer:
Explanation:
The row for month 25 shows that after <em>twenty-five payments</em> <u>the balance of the loan is $10,356.03</u>
You are told that the<em> loan amount or principal is $ 19,900</em>.
From those two data, you can calculate <em>how much of the principal has been paid off after </em>25 months, because the amount paid off is equal to the loan less the balance after 25 payments:
- Principal paid off = $ 19,900 - $ 10,356.03 = $9,543.97
In linear models there is a constant additve rate of change. For example, in the equation y = mx + b, m is the constanta additivie rate of change.
In exponential models there is a constant multiplicative rate of change.
The function of the graph seems of the exponential type, so we can expect a constant multiplicative exponential rate.
We can test that using several pair of points.
The multiplicative rate of change is calcualted in this way:
[f(a) / f(b) ] / (a - b)
Use the points given in the graph: (2, 12.5) , (1, 5) , (0, 2) , (-1, 0.8)
[12.5 / 5] / (2 - 1) = 2.5
[5 / 2] / (1 - 0) = 2.5
[2 / 0.8] / (0 - (-1) ) = 2.5
Then, do doubt, the answer is 2.5
