The values are a = 7, b = -9, c = -18.
<u>Step-by-step explanation:</u>
The given quadratic equation is 
The general form of the quadratic equation is 
where,
- a is the coefficient of x².
- b is the coefficient of x.
- c is the constant term.
Now, you have to modify the given quadratic equation similar to the general form of quadratic equation.
So, bring the constant term 18 to the left side of the equation for equating it to zero.
⇒ 
Compare the above equation with general form
⇒ a = 7
⇒ b = -9
⇒ c = -18
Therefore, the values of a, b, and c are 7, -9 and -18.
Answer:
a) 0.75
b) 0.0625
c) 0.1875
d) 0.375
Step-by-step explanation:
Let's start by first finding the probability a teacher orders 6 boxes. Since it is a four sided dice, the probability of getting a 1 is going to be 0.25.
Similarly, for any other number on the dice, the teacher orders 2 boxes. We can think of this as NOT rolling a 1. Using our previous answer, this comes out to be: 1 - 0.25 = 0.75
It should be remembered in the following answers that teachers ordering 6 or 2 boxes are not influenced by the results of other teachers. These are statistically independent events.
a) As given above, this probability is 0.75
b) The probability that both teachers order 6 boxes will be their individual probabilities multiplied. This comes out to be: 0.25 x 0.25 = 0.0625
c) Like in part (b), this is both of their probabilities multiplied:
0.25 x 0.75 = 0.1875
d) This is nearly the same as part (c), but with a little twist. The order matters. There are two scenarios:
- First teacher gets 6 boxes, and the second gets 2.
- First teacher gets 2 boxes, and the second gets 2.
Both of these events have a probability of 0.1875, as shown in (c). To get the total probability of this event happening, we must add these together:
0.1875 + 0.1875 = 0.375
Answer:
P ( X > 5 ) = 72,2 %
Step-by-step explanation:
The probability of success ( outcomes bigger than 5 )
If dice 1 outcome is 6 no matter wich outcome we get from dice 2 all events are successful, the we have 6 outcomes
If dice 1 outcome is 5 we also have 6 outcomes
If dice 1 outcomes is 4 we have 5 positive outcomes
If dice 1 outcome is 3 we have 4 positive outcomes
If dice 1 outcome is 2 we have 3 positive outcomes
if dice 1 outcome is 1 we have 2 positive outcomes
Total evaluating dice 1: positive outcomes 26
We will get the sames results analysing dice 2 then we have a total of
52 successful events
And total numbers of outcomes is 36 + 36 = 72
Then
P ( X > 5 ) = 52/72
P ( X > 5 ) = 0,722
P ( X > 5 ) = 72,2 %
Answer:
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Answer:
the answer is b
Step-by-step explanation:
got it right on the test
