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zhuklara [117]
2 years ago
6

Combine like terms in the given polynomial. Then, evaluate for x = 4, y = – 2.

Mathematics
1 answer:
EastWind [94]2 years ago
5 0

Answer:

- 2 x y^2+3 x^2 y -xy

-120

Step-by-step explanation:

xy – 2xy + 3x^2 y — 4x y^2 + 2xy^2

Combine like terms

xy – 2xy + 3x^2 y — 4x y^2 + 2xy^2

- x y+3 x^2 y - 2 x y^2

Let x = 4 y = -2

-(4)(-2) +3(4)^2 (-2) -2(4)(-2)^2

Exponents first

-(4)(-2) +3(16) (-2) -2(4)(4)

Multiply

+8 -96-32

Add and subtract

-120

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Alice's garden produced 17 yellow tomatoes this year. She also grew 18 roma
Sever21 [200]

Answer:

C

Step-by-step explanation:

You add both types of tomatoes together to get the total amount of tomatoes

4 0
3 years ago
Gianna drove 176 miles in 8 hours. On average, how fast did she drive in miles per hour? Express your answer in simplest form.
vesna_86 [32]

Answer:

22

Step-by-step explanation:

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4 0
3 years ago
X^2+25<br><br> A.(x+5)(x+5)<br> B.(x+5)(x-5)<br> C.(x-5)(x/5)<br> D.prime
adell [148]
It’s prime because none of the other answers work.
8 0
3 years ago
Nia has number cards 2,3,8,9, and 5 . What are the different way bus can arrange the cards to show only even numbers with 2 in t
zhuklara [117]
There are 6 different ways:

23,598
23,958
25,398
25,938
29,538
29,358

8 0
3 years ago
Find the sum of the least and greatest two digit prime numbers whose digits are also prime?
adoni [48]
First, we need to know the smallest two digit prime number. It can't start with one, since one is not prime, so it must start with two (or be in the twenties.) 20 is divisible by 2, 4, 5, and 10, 21 is divisible by 7 and 3, 22 is divisible by 2 and 11, so the smallest prime number is 23.

Now we need the largest two-digit prime number. It cannot start with nine or eight, since both are composite, so it must start with seven (be in the seventies.) 79 is the largest integer in the seventies and also happens to be prime, so there's our largest two digit prime number.

now we just need to add them for the sum:
23+79=102

hope I helped, and let me know if you have any questions :D
7 0
3 years ago
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