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svlad2 [7]
3 years ago
6

3

Mathematics
1 answer:
Verizon [17]3 years ago
6 0
I’m pretty sure it’s c :)
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How many 4-letter passords can be made using the letters A thought Z if...
Kazeer [188]

Answer:

26^4 if repetition is allowed, 26 \times25\times24\times23 if repetition is not allowed.

Step-by-step explanation:

For the first case, we have a choice of 26 letters <em>each step of the way. </em>For each of the 26 letters we can pick for the first slot, we can pick 26 for the second, and for each of <em>those</em> 26, we can pick between 26 again for our third slot, and well, you get the idea. Each step, we're multiplying the number of possible passwords by 26, so for a four-letter password, that comes out to 26 × 26 × 26 × 26 = 26^4 possible passwords.

If repetition is <em>not </em>allowed, we're slowly going to deplete our supply of letters. We still get 26 to choose from for the first letter, but once we've picked it, we only have 25 for the second. Once we pick the second, we only have 24 for the third, and so on for the fourth. This gives us instead a pretty generous choice of 26 × 25 × 24 × 23 passwords.

8 0
3 years ago
5. Roy eats 2 cereal bars every morning. Each box has a total of 12 bars. How many days will it take Roy to
Sergeu [11.5K]

Answer:

hi

Step-by-step explanation:

hi

4 0
3 years ago
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Solve for x. Round your answer to the nearest tenth. 19, 17
luda_lava [24]

Step-by-step explanation:

since what ? there is nothing here.

3 0
3 years ago
Use Fermat's Little Theorem to determine 7^542 mod 13.
m_a_m_a [10]

a^{p-1} \equiv 1 \pmod p where p is prime, a\in\mathbb{Z} and a is not divisible by p.

7^{13-1}\equiv 1 \pmod {13}\\7^{12}\equiv 1 \pmod {13}\\\\542=45\cdot12+2\\\\7^{45\cdot 12}\equiv 1 \pmod {13}\\7^{45\cdot 12+2}\equiv 7^2 \pmod {13}\\7^{542}\equiv 49 \pmod{13}

4 0
3 years ago
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Extend the sequence and then complete the
andrew-mc [135]

Answer:

l

Step-by-step explanation:

A sequence is an ordered list of numbers.....

A term is an element in a sequence.

You can expand a sequence by finding and writing....

The next term in the sequence is A = (general term)

8 0
3 years ago
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