Answer:
Sheridan's Work is correct
Step-by-step explanation:
we know that
The lengths side of a right triangle must satisfy the Pythagoras Theorem
![c^{2}=a^{2}+b^{2}](https://tex.z-dn.net/?f=c%5E%7B2%7D%3Da%5E%7B2%7D%2Bb%5E%7B2%7D)
where
a and b are the legs
c is the hypotenuse (the greater side)
In this problem
Let
![a=7\ cm\\c=13\ cm](https://tex.z-dn.net/?f=a%3D7%5C%20cm%5C%5Cc%3D13%5C%20cm)
substitute
![13^{2}=7^{2}+b^{2}](https://tex.z-dn.net/?f=13%5E%7B2%7D%3D7%5E%7B2%7D%2Bb%5E%7B2%7D)
Solve for b
![169=49+b^{2}](https://tex.z-dn.net/?f=169%3D49%2Bb%5E%7B2%7D)
![b^{2}=169-49](https://tex.z-dn.net/?f=b%5E%7B2%7D%3D169-49)
![b^{2}=120](https://tex.z-dn.net/?f=b%5E%7B2%7D%3D120)
![b=\sqrt{120}\ cm](https://tex.z-dn.net/?f=b%3D%5Csqrt%7B120%7D%5C%20cm)
![b=10.95\ cm](https://tex.z-dn.net/?f=b%3D10.95%5C%20cm)
we have that
<em>Jayden's Work</em>
![a^{2}+b^{2}=c^{2}](https://tex.z-dn.net/?f=a%5E%7B2%7D%2Bb%5E%7B2%7D%3Dc%5E%7B2%7D)
![a=7\ cm\\b=13\ cm](https://tex.z-dn.net/?f=a%3D7%5C%20cm%5C%5Cb%3D13%5C%20cm)
substitute and solve for c
![7^{2}+13^{2}=c^{2}](https://tex.z-dn.net/?f=7%5E%7B2%7D%2B13%5E%7B2%7D%3Dc%5E%7B2%7D)
![49+169=c^{2}](https://tex.z-dn.net/?f=49%2B169%3Dc%5E%7B2%7D)
![218=c^{2}](https://tex.z-dn.net/?f=218%3Dc%5E%7B2%7D)
![c=\sqrt{218}\ cm](https://tex.z-dn.net/?f=c%3D%5Csqrt%7B218%7D%5C%20cm)
![c=14.76\ cm](https://tex.z-dn.net/?f=c%3D14.76%5C%20cm)
Jayden's Work is incorrect, because the missing side is not the hypotenuse of the right triangle
<em>Sheridan's Work</em>
![a^{2}+b^{2}=c^{2}](https://tex.z-dn.net/?f=a%5E%7B2%7D%2Bb%5E%7B2%7D%3Dc%5E%7B2%7D)
![a=7\ cm\\c=13\ cm](https://tex.z-dn.net/?f=a%3D7%5C%20cm%5C%5Cc%3D13%5C%20cm)
substitute
![7^{2}+b^{2}=13^{2}](https://tex.z-dn.net/?f=7%5E%7B2%7D%2Bb%5E%7B2%7D%3D13%5E%7B2%7D)
Solve for b
![49+b^{2}=169](https://tex.z-dn.net/?f=49%2Bb%5E%7B2%7D%3D169)
![b^{2}=169-49](https://tex.z-dn.net/?f=b%5E%7B2%7D%3D169-49)
![b^{2}=120](https://tex.z-dn.net/?f=b%5E%7B2%7D%3D120)
![b=\sqrt{120}\ cm](https://tex.z-dn.net/?f=b%3D%5Csqrt%7B120%7D%5C%20cm)
![b=10.95\ cm](https://tex.z-dn.net/?f=b%3D10.95%5C%20cm)
therefore
Sheridan's Work is correct
Divide each side by 16
x = 3
Answer:
1x+1
Step-by-step explanation:
just open the parentheses
(4x+y)+5
20x+5y
20x+5y+0
third term is zero
Answer:
m∠ TRS = 60° , m∠ SRW = 120°
Step-by-step explanation:
First, find x
∠TRS = ∠VRW (vertically opposite angles are equal)
x + 40° = 3x
x - 3x = -40
-2x = -40
x = -40/-2
x = 20
m∠ TRS = 60° [x + 40 = 20+40 = 60]
m∠ SRW + m∠ TRS = 180° (linear pair)
m∠ SRW + 60° = 180°
m∠ SRW = 180° - 60°
m∠ SRW = 120°
hope this helps you