Let us find the co ordinates of each vertex of the triangle .
Vertex A ( in firs second quadrant) = ( -5 ,3)
vertex B in third quadrant = ( -5, -5)
vertex C in fourth quadrant = ( 4, -2)
let us use distance formula AB^2 = ( -5 - 3)^2 + (-5 - -5 )^2 = 64 + 0
AB= 8
BC^2 = ( -2 - -5 )^2 + ( 4 - - 5)^2 = 9 + 81 = 90
BC = 9.48
AC^2 = ( -2 -3)^2 +( 4- -5)^2 = 25 + 81 = 106
AC= 10.29
Perimeter = sum of length of AB+ BC+ Ac = 8 + 10.29 + 9.48= 22.77
2−(−4)+3+(−6)−(−2)2, minus, left parenthesis, minus, 4, right parenthesis, plus, 3, plus, left parenthesis, minus, 6, right pare
Yuki888 [10]
Answer: 7
Step-by-step explanation:
2−(−4)+3+(−6)−(−2)2
solution:
– x – = +
– x + = –
= 2−(−4)+3+(−6)−(−2)2
= 6 + 3 + ( – 6) – ( 2 ) 2
= 9 + ( –6 ) – ( –2 ) 2
= 3 – (–2)2
= 3 – ( –4 )
= 7
We have the following function:
N (k):
Where, the indepent variable is k
The dependent variable is N
For the function:
k (n):
the independent variable is n
The dependent variable is k
Thus,
N (12) = 4
k (4) = 12
Answer:
TRUE
option A
Answer:
<em>0.5306</em>
<em>0.5694</em>
Step-by-step explanation:
USing the formuls for calculating the confidence interval for the population proportion;
CI = p±Z*√[p(1-p)/n]
p is the percentage proportion of the population 55%
Z is the z-score at 99% confidence interval = 2.576
n is the sample size = 1079
CI = 0.55 ± 2.576*[0.55(1-0.55)/√1079]
CI = 0.55 ± 2.576*[0.55(0.45)/√1079]
CI = 0.55 ± 2.576*[0.2475/√1079]
CI = 0.55 ± 2.576*[0.2475/32.85]
CI = 0.55 ± 2.576*[0.00753]
CI = 0.55 ±0.0194
CI =(0.55-0.0194, 0.55+0.0194)
CI = (0.5306, 0.5694)
<em>Hence, a 99% confidence interval of the proportion of the population that will support such a law is 0.5306</em><em>0.5694</em>
Answer:
b. -1/2
c. 3/2
d. 1/-5
Step-by-step explanation:
Plug in the values into the slope formula and reduce/simplify
