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Strike441 [17]
2 years ago
6

Using the equation x= 12- 3y, complete the ordered pair (___,-5).

Mathematics
1 answer:
cupoosta [38]2 years ago
3 0

27 because like 12-3time -5 which would be -15 and then with thte 12-(-15)=27 SO THE ANSWER IS 27

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Is the following number rational or irrational?
zubka84 [21]

Answer:

B.

Step-by-step explanation:

Irrational as π is irrational.

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56 projects 5:9 ratio divide
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The answer is 4:4 it takes 4 of each





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2 years ago
I Need Help Failing Badly Geometry Is Hard!!
Korvikt [17]

Answer:

Choice A. Segment LM is congruent to segment LO.

Step-by-step explanation:

Triangles LMX and LOX are right triangles since we see that each one has a right angle.

Segment LX is congruent to itself. Segment LX is a side of both triangles. It is a leg of both triangles, so we already have a leg of one triangle congruent to a leg of the other triangle.

For the HL theorem to work, we need a leg and the hypotenuse of one triangle to be congruent to the corresponding parts of the other triangle. Since we already have a pair of legs, we need a pair of hypotenuses.

The hypotenuses of the triangles are segments LM and LO.

Answer: A. Segment LM is congruent to segment LO.

3 0
3 years ago
1. In ABC, A=45 degrees, B=75 degrees, and BC=12. What is the length of AB?
Aleksandr-060686 [28]

We know that sum of the interior angles of any triangle equal 180° :

So :

A + B + C = 180°

45° + 75° + C = 180°

120° + C = 180°

Both sides minus ( 120°) :

C = 180° - 120°

C = 60°

_________________________________

According to the theorem of sinuses :

\frac{AB}{ \sin(C) } =  \frac{BC}{ \sin(A) } \\

\frac{AB}{ \sin(60) } =  \frac{12}{ \sin(45) } \\

\frac{AB}{ \frac{ \sqrt{3} }{2} } =  \frac{12}{ \frac{ \sqrt{2} }{2} } \\

Multiply \:  both \:  sides \:  by \:   \frac{ \sqrt{3} }{2}

AB =  \frac{24}{ \sqrt{2} } \times  \frac{ \sqrt{3} }{2} \\

AB =  \frac{12 \sqrt{3} }{ \sqrt{2} } \\

AB =  \frac{2 \times 6 \sqrt{3} }{ \sqrt{2} } \\

AB =  \frac{ ({ \sqrt{2} })^{2} \times 6 \sqrt{3}  }{ \sqrt{2} }  \\

AB =  \frac{ \sqrt{2} \times  \sqrt{2} \times 6 \sqrt{3}   }{ \sqrt{2} } \\

AB =  \frac{ \sqrt{2} \times  6 \sqrt{3}   }{1} \\

AB =  \sqrt{2} \times 6 \sqrt{3}

AB = 6 \sqrt{2 \times 3}

AB = 6 \sqrt{6}

_________________________________

I think this is the correct answer.

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

4 0
3 years ago
Solve for x and y<br> 3x + 2y = 16<br> 7x + y = 19
alukav5142 [94]

Answer:

  (x, y) = (2, 5)

Step-by-step explanation:

Double the second equation and subtract the first:

  2(7x +y) -(3x +2y) = 2(19) -(16)

  11x = 22

  x = 2

In the second equation, ...

  7(2) +y = 19

  y = 19 -14 = 5

The solution is (x, y) = (2, 5).

3 0
3 years ago
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