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Ainat [17]
3 years ago
9

What is the correct 3a(8a-6b)

Mathematics
1 answer:
seropon [69]3 years ago
3 0
You would distribute the 3a to the other terms inside the parenthesis:

3a*8a=24a^2
3a*(-6b)=-18ab

Your answer would be 24a^2-18ab
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Christine had p coins. Then she found 87 more coins in a drawer. Write an expression that shows how many coins Christine has now
pishuonlain [190]
Well she started with P. She then found 87 ADDING that to her original P meaning she has P+87 coins :)
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4 years ago
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Two times the sum of a number and 7
GenaCL600 [577]

Answer:

2(x+7)

Step-by-step explanation:

i hope this helps

4 0
3 years ago
Please let me know if this is correct and if not what is the correct answer. Thanks
vlada-n [284]
There’s nothing on the picture
6 0
2 years ago
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In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g
KIM [24]

Answer:

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

All girls from the first group:

20 students, so N = 20

10 girls, so k = 10

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163

All girls from the second group:

20 students, so N = 20

5 girls, so k = 5

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006

All girls from the third group:

20 students, so N = 20

8 girls, so k = 8

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

7 0
3 years ago
2c+17.6 =6 / 4 SOLVE give your answer as a decimal get brainly
tamaranim1 [39]

Answer:

-8.05

Step-by-step explanation:

In order to solve for C you first have to subtract 17.6 from both sides.

2c=(6/4)-17.6

6/4 is 1.5

1.5-17.6=-16.1

2c=-16.1

c=-8.05

8 0
3 years ago
Read 2 more answers
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