Soooo this was from yesterday and well i need to finish it so help

1. What name is given to the shaded region?

mario62 [17]

Answer:

1.sector 2. chords

Step-by-step explanation:

chord of a circle is a straight line segment whose endpoints both lie on a circular arc. ... More generally, a chord is a line segment joining two points on any curve, for instance, an ellipse. A chord that passes through a circle's center point is the circle's diameter.

3 0

3 years ago

Please help I don’t understand this and I can’t figure it out.

ryzh [129]

So the groups of angles that make a line (like 130 and i or p a and t) should equal 180. however, the triangles should also equal 180. so in this case for the top row, we know that 130+j=180. since 180-130=50 (i did the inverse of addition, subtraction), j=50. now let’s say for that triangle that your top two angle measures were the 50 we just found and the 70 you have written just as an assumption but i have no clue what you were actually given. since triangles angles must equal 180, 50+70+that angle =180. 50+70=120, so if we do the inverse of 180-120=60, we find out that the bottom angle is 60 degrees.

7 0

3 years ago

A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as

Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let X = number of seconds in the batch.

The probability of the random variable X is, p = 0.31.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

$P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888$

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

$=1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776$

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

$={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453$