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1) place the compass needle on the external point r.2) make the compass width greater than the distance from r to the given line.
3) draw an arc cutting the given line at two points.
4) mark and label the points of intersection p and q.
5) without changing the compass width, move the compass needle to q and draw another arc below the line crossing the previous arc.
6) move the compass needle to p and make an arc below the line.
7) mark and label the point of intersection s.
8) draw a line from the external point r to the point where the arcs intersect, s.
9) line rs is perpendicular to line pq and passes through the external point r.
Answer:
x=5
Step-by-step explanation:
First, let's understand logarithms.
When there is no base given, like in this problem's right side of the equation, the base is automatically 10.
So, let's re-write that.
Now, let's test a few of the numbers out. For brevity, I already know it's 3. Let's show you why.
The ratio of 114 hours to 13 days is 19:52.
<h3>How to calculate the ratio?</h3>
It should be noted that ratio is simply used to show the comparison between two things that are illustrated.
In this case, we want to calculate the ratio of 114 hours to 13 days. It should be noted that 24 hours make one day. Therefore, 13 days will be:
= 13 × 24 = 312 hours.
The ratio of 114 hours to 13 days will be:
= 114 / 312
= 19 / 52
The ratio is 19:52.
Learn more about ratio on:
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Answer:
p = ½ (x₁ + x₂)
q = a (x₁x₂ − ¼ (x₁ + x₂)²)
Step-by-step explanation:
y = a (x − x₁) (x − x₂)
Expand:
y = a (x² − x₁x − x₂x + x₁x₂)
y = a (x² − (x₁ + x₂)x + x₁x₂)
Distribute a to the first two terms:
y = a (x² − (x₁ + x₂)x) + ax₁x₂
Complete the square:
y = a (x² − (x₁ + x₂)x + ¼(x₁ + x₂)²) + ax₁x₂ − ¼ a(x₁ + x₂)²
y = a (x − ½ (x₁ + x₂))² + a (x₁x₂ − ¼ (x₁ + x₂)²)
Therefore:
p = ½ (x₁ + x₂)
q = a (x₁x₂ − ¼ (x₁ + x₂)²)
