Answer:
7.0
Step-by-step explanation:
In ΔVWX, the measure of ∠X=90°, the measure of ∠W=9°, and WX = 8.7 feet. Find the length of XV to the nearest tenth of a foot.
First we use sin(a+b)= sinacosb+sinbcosa
and cos(a+b)=cosa cosb -sinasinb
tan(x+pi/2)= sin(x+pi/2) / cos(x+pi/2)
and sin(x+pi/2) = sinxcospi/2 + sinpi/2cosx =cosx,
<span>cos(x+pi/2) = cosxcospi/2- sinxsinpi/2= - sinx,
</span> because <span>cospi/2 =0, </span>and <span>sinpi/2=1
</span><span>=tan(x+pi/2)= sin(x+pi/2) / cos(x+pi/2)= cosx / -sinx = -1/tanx = -cotx
</span>from where <span>tan(x+pi/2)=-cotx</span>
The easiest way is to make equations y=2400x+30000 and y=2000+36000
and then put that in the calculator and go to table and the point they intersect at is (15,66000)
It depends on what you are rounding off to.
If you are round it off to the nearest ten, you must look at the unit number.
If you are rounding off to the nearest hundred, you must look at the ten number.
In this case I think they are asking to round to the nearest hundred. Now we must look at the ten number, which is the number after the 'hundred' number.
The ten number is '5' and the hundred number is '1'. If the ten number is 5 or above, it changes to 0 and it makes the hundred number one higher.
So because the ten number is 5, it changes to 0 and it makes the hundred number one higher, to become 2.
The number is now 200.
