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2 years ago

Which boxes do I select?

Mathematics

1 answer:

oee [108]2 years ago

8 0

Answer:

4th box

Step-by-step explanation:

You might be interested in

1. 25% of what is 16 2. 76 is what percent of 80

Allisa [31]

1.64
2. 95%
Hope this helps you.

6 0

3 years ago

Someone please HELP!?

jeka94

A negative exponent just means that the base is on the wrong side of the fraction line, so you need to flip the base to the other side.

For example

$x^{-2}=\frac{1}{x^2}$

or

$( \frac{2}{5} )^{-4}=( \frac{5}{2} )^4$

***************************************
$(8r^{-5})^{-3}$

$(8* \frac{1}{r^5} )^{-3} \\\\( \frac{8}{r^5} )^{-3}
 \\ \\ ( \frac{r^5}{8} )^3
\\\\ \mathrm{Apply\:exponent\:rule}:\quad *\left(\frac{a}{b}\right)^c=\frac{a^c}{b^c} \ \ \ \ \ \ \ \ \ \ \ \ *(a^b)^c=a^{bc}
 \\\\( \frac{r^{15}}{8^3} )
\\\\( \frac{r^{15}}{512} )$

The answer is "D"

7 0

3 years ago

Show two different ways to factor −4x −28.

vazorg [7]

Step-by-step explanation:

-4x - 28 = -4(x + 7) or 4(-x - 7)

Topic: Algebraic factorization

If you like to venture further, do check out my insta (learntionary) where I regularly post useful math tips! Thank you!

8 0

3 years ago

1/-3/x^6 simplest radical form

Contact [7]

Answer:

The answer would be -x/3x^6

Step-by-step explanation:

The first step that you should take is apply the fraction rule.

That would make it -1/3/x^6

Then apply the fraction rule again.

That would make it. 1/3/-x^6

Then apply the last fraction rule.

That would make it -1/3x^6

5 0

3 years ago

Let V be the volume of the solid obtained by rotating about the y-axis the region bounded by y=√x and y=x^2. Find V either by sl

Ede4ka [16]

Answer:

The volume of the solid is $3\pi/10$

Step-by-step explanation:

In this case, the washer method seems to be easier and thus, it is the one I will use.

Since the rotation is around the y-axis we need to change de dependency of our variables to have $f(x)\rightarrow f(y)$ . Thus, our functions with $y$ as independent variable are:

$x=\sqrt{y}\\ x=y^2$

For the washer method, we need to find the area function, which is given by:

$A=\pi\cdot [(\rm{outer\ radius)^2 -(\rm{inner\ radius)^2 ]$

By taking a look at the plot I attached, one can easily see that for a rotation around the y-axis the outer radius is given by the function $x=\sqrt{y}$ and the inner one by $x=y^2$ . Thus, the area function is:

$A(y)=\pi\cdot [(\sqrt{y} )^2-(y^2)^2]\\A(y)=\pi\cdot (y-y^4)$

Now we just need to integrate. The integration limits are easy to find by just solving the equation $\sqrt(y)=y^2$ , which has two solutions $y=0$ and $y=1$ . These are then, our integration limits.

$V=\pi\int_{0}^1 (y-y^4)dy\\ V=\pi (\int_{0}^1 ydy - \int_{0}^1 y^4dy)\\ V=\pi/2-\pi/5\\\boxed{V=3\pi/10}$

3 0

3 years ago