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tangare [24]
3 years ago
6

What two numbers have a product of 16 and a sum of 8?

Mathematics
1 answer:
Vaselesa [24]3 years ago
3 0
4 because 4 x 4 =16 and 4+4=8
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Step-by-step explanation:

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The pie chart shows information about the voters in an election 2800 more women voted than men work out the total number of vote
Cerrena [4.2K]

The angle subtended by the women voters are 100° more than the angle subtended by the men voters.

  • The total number of voters are <u>10080 voters</u>

Reasons:

The angle subtended by the men on the pie chart = 130°

The number of women = 2800 + The number of men

Therefore;

Angle subtended by the women voters on the pie chart = 360° - 130° = 230°

The difference between the angle representing women and the angle

representing men = 230° - 130° = 100°

Therefore;

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Which by common ratios gives;

\dfrac{100^{\circ}}{360^{\circ}} = \dfrac{2800}{Total \ number \  of \ voters }

100 × Total number of voters = 2800 × 360

The \  total \  number  \ of  \ voters = \dfrac{2800 \times 360}{100}  = 10080

The total number of voters = <u>10080</u>

Learn more here:

brainly.com/question/20431949

6 0
3 years ago
Which fraction has a value greater than 0.4
hodyreva [135]
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6 0
3 years ago
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Kona wants to bake 30 loaves of bananas bread and nut bread one is 2.50 and other is 2.75 she wants to make are lasts 44$ write
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Step-by-step explanation:

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2 years ago
A new security system needs to be evaluated in the airport. The probability of a person being a security hazard is 4%. At the ch
ivolga24 [154]

Answer:

(a) 0.9412

(b) 0.9996 ≈ 1

Step-by-step explanation:

Denote the events a follows:

P = a person passes the security system

H = a person is a security hazard

Given:

P (H) = 0.04,\ P(P^{c}|H^{c})=0.02\ and\ P(P|H)=0.01

Then,

P(H^{c})=1-P(H)=1-0.04=0.96\\P(P|H^{c})=1-P(P|H)=1-0.02=0.98\\

(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})

The value of P (P) is:

P(P)=P(P|H)P(H)+P(P|H^{c})P(H^{c})\\=(0.01\times0.04)+(0.98\times0.96)\\=0.9412

Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

P(H^{c}|P)=\frac{P(P|H^{c})P(H^{c})}{P(P)} \\=\frac{0.98\times0.96}{0.9412} \\=0.9996\\\approx1

Thus, the probability that a person who passes through the system is without any security problems is approximately 1.

7 0
3 years ago
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