$3\log_7y + 4(\log_7x - 5\log_7z)\\\log_7y^{3} + 4(\log_7x - 5\log_7z)\\\log_7y^{3} + 4(\log_7x - \log_7z^{5})\\\log_7y^{3} + 4(\log_7(\frac{x}{z^{5}}))\\\log_7y^{3} + \log_7(\frac{x}{z^{5}})^{4}\\\log_7(y^{3} \times (\frac{x}{z^5{5}})^{4})$

4 0

3 years ago

What is the slope of the line perpendicular to the y=-1/5x-9? <br><br> Plz help me

labwork [276]

Answer:

Step-by-step explanation:

Remember that the slope of a line that is perpendicular to a given line is the negative reciprocal of the slope of the given line.

Here we are given the line y = -(1/5)x - 9. The slope is (-1/5). The negative reciprocal of this is +5. That's the answer you wanted.

4 0

4 years ago