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shusha [124]
3 years ago
8

Which best describes the incenter of a triangle?

Mathematics
2 answers:
ira [324]3 years ago
7 0

Answer:

D. The point where the three angle bisectors of the triangle intersect

Step-by-step explanation:

sineoko [7]3 years ago
6 0

Answer:

The statement that best describes the incenter of a triangle is that, it is the point where the three angle bisectors of the triangle intersect. In geometry, an incenter of a triangle is described as the triangle center.

Step-by-step explanation:

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Ashley had a doll collection consisting of 43 dolls. As she got older she ended up selling some. She only kept her
Marianna [84]

Answer:

27.9 i think in in a fraction 12 / 43

Step-by-step explanation:

7 0
3 years ago
Which statement is true about the parts of this expression?
olganol [36]
<span>A) The constant is 7.5.  FALSE.  7.5 is a coefficient, not a constant.

</span><span>B) The coefficients are 7.5 and -9.  FALSE.  The coefficients are 7.5, -1/9 and 2.  50, being a constant, could be regarded as a coefficient in this case.

</span><span>C) The variables are x and y.  FALSE.  There are three variables:  x, y and z.

</span><span>D) The like terms are 7.5y and 2y.  TRUE.  The variable (y) is the same in each term.</span><span>

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4 0
3 years ago
Read 2 more answers
Which of the following is not a kind of consumer credit? a. installment credit b. personal loans c. service credit d. marginal c
Nat2105 [25]
A) installment credit
B ) personal loan
C)
service credit
D) marginal credit 






7 0
3 years ago
Read 2 more answers
A survey collected data on annual credit card charges in seven different categories of expenditures: transportation, groceries,
Andru [333]

Answer:

A. Null and alternative hypothesis:

H_0: \mu_d=0\\\\H_a:\mu_d\neq 0

B. Yes. At a significance level of 0.05, there is enough evidence to support the claim that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

P-value = 0.00002

C. As the difference is calculated as (population 1 − population 2), being population 1: groceries and population 2: dinning out, and knowing there is evidence that the true mean difference is positive, we can say that the groceries annual credit card charge is higher than dinning out annual credit card charge.

The point estimate is the sample mean difference d=$840.

The 95% confidence interval for the mean difference between the population means is (490, 1190).

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

Then, the null and alternative hypothesis are:

H_0: \mu_d=0\\\\H_a:\mu_d\neq 0

The significance level is 0.05.

The sample has a size n=42.

The sample mean is M=840.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=1123.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{1123}{\sqrt{42}}=173.2827

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{840-0}{173.2827}=\dfrac{840}{173.2827}=4.848

The degrees of freedom for this sample size are:

df=n-1=42-1=41

This test is a two-tailed test, with 41 degrees of freedom and t=4.848, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=2\cdot P(t>4.848)=0.00002

As the P-value (0.00002) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

At a significance level of 0.05, there is enough evidence to support the claim that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

We have to calculate a 95% confidence interval for the mean difference.

The t-value for a 95% confidence interval and 41 degrees of freedom is t=2.02.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=2.02 \cdot 173.283=350

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 840-350=490\\\\UL=M+t \cdot s_M = 840+350=1190

The 95% confidence interval for the mean difference is (490, 1190).

7 0
3 years ago
What is 6.37 × 104 written in standard form?   A. 63,700   B. 637,000   C. 6370   D. 637
Setler [38]
= 6.37 * 10^4 = 637 * 10^2 = 63700

In short, Your Answer would be Option A

Hope this helps!
8 0
3 years ago
Read 2 more answers
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