Ask question

Ask question

All categories

bogdanovich [222]

2 years ago

14

On a math test , you scored 69 out of a total of 75 points. what percent did you get?

2 answers:

Gelneren [198K]2 years ago

8 0

Simple, to find the percentage you scored on your test, take

What you got= 69
Total=75

Divide,

69/75=0.92

Finally, multiply by 100.

0.92*100=92

You got a 92% on the math test.

topjm [15]2 years ago

3 0

92% You would divide 69 by 75 then multiply by 100

You might be interested in

Find surface area of the prism

Vika [28.1K]

SA=(a+b+c) h+bh
=(5+12+13)*4+5*12
=20*4+60
=80+60
=140 cm squared

6 0

2 years ago

In JKL, k=4.1 cm,j=3.8 cm and angle J=Q3^ Find all possible values of angle K , to the nearest inch of a degree .

spayn [35]

Answer:

74.0°

Step-by-step explanation:

In triangle JKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°. Find all possible values of angle K, to the nearest 10th of a degree

Solution:

A triangle is a polygon with three sides and three angles. Types of triangles are right angled triangle, scalene triangle, equilateral triangle and isosceles triangle.

Given a triangle with angles A, B, C and the corresponding sides opposite to the angles as a, b, c. Sine rule states that for the triangle, the following holds:

$\frac{a}{sin(A)}=\frac{b}{sin(B)}=\frac{c}{sin(C)}$

In triangle JKL, k=4.1 cm, j=3.8 cm and angle J=63°.

Using sine rule, we can find ∠K:

$\frac{k}{sin(K)}=\frac{j}{sin(J)} \\\\\frac{4.1}{sin(K)}=\frac{3.8}{sin(63)} \\\\sin(K)=\frac{4.1*sin(63)}{3.8}\\\\sin(K)=0.9613\\\\K=sin^{-1} (0.9613)\\\\K=74.0^o \\$

6 0

2 years ago

True or false: f(x) is a function

EastWind [94]

Answer:

It's true

Step-by-step explanation:

f(x) and g(x) are another name to use instead of y

A function is an equation which, for every x, has only one response for y. A function assigns each input of a given form to exactly one output.

7 0

2 years ago

Evaluate the function when x=−2, 0, and 5. g(x)=3x−2

kipiarov [429]

I hope this helps....

x=-2
g(-2)= 3(-2)-2
= -6-2
g(-2)= -8

x=0
g(0)= 3(0)-2
=-2

x=5
g(5)=3(5)-2
g(5)=13

5 0

3 years ago

Read 2 more answers

In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol

Julli [10]

Answer:

$0.071,1.928$

Step-by-step explanation:

Downtown Store North Mall Store

Sample size n 25 20

Sample mean $\bar{x}$ $9 $8

Sample standard deviation s $2 $1

$n_1=25\\n_2=20$

$\bar{x_1}=9\\ \bar{x_2}=8$

$s_1=2\\s_2=1$

$x_1-x_2=9-8=1$

Standard error of difference of means = $\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}$

Standard error of difference of means = $\sqrt{\frac{2^2}{25}+\frac{1^2}{20}}$

Standard error of difference of means = $0.458$

Degree of freedom = $\frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}$

Degree of freedom = $\frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}$

Degree of freedom =36

So, z value at 95% confidence interval and 36 degree of freedom = 2.0280

Confidence interval = $(x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)$

Confidence interval = $1-(2.0280)\times 0.458,1+(2.0280)\times 0.458$

Confidence interval = $0.071,1.928$

Hence Option A is true

Confidence interval is $0.071,1.928$

4 0

2 years ago