To get the extrema, derive the function.
You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
Since you are on a closed interval [-1, 1], those points can also have an extrema.
Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
Thus, the maximum is at (-1, 5).
Answer:
170
Step-by-step explanation:
30 x 3 then do 10 x 8
90 + 80
Answer:
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Thanks So MUCH!!!
Step-by-step explanation:
Answer:
Don't lisen to that the anwer is 0.3125
Step-by-step explanation:
