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Morgarella [4.7K]

3 years ago

14

a business has the following entires in their budget: $45 expense, $980 income, $249 income, $780 expense, $437 expense. what is

the balance of the business's budget?

1 answer:

Anettt [7]3 years ago

6 0

-$45 +$980 +$249 -$780 - $437 = -$33

The business budget has a negative balance of $33.

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length = 14 feet

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Subway creates a paid promotion featuring a different 6-inch sub of the day each day of the week. The sub of the day is only $3.

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Based on the information provided, the promotion method subway is using is sales promotion.

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3 years ago

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3 years ago

Use the picture to find each of the following

goldfiish [28.3K]

$\large{ \tt{☄ANSWERS \: + \: REASONS}} :$

$\large{ \tt{ \angle \: 7 = \boxed{ \tt{38 \degree}}}} \: ( \text{Being \: alternate \: angles)}$

$\large{ \tt{38 \degree + \angle 4 = 180 \degree}}( \text{Sum \: of \: co - interior \: angles}$

$\: \: \: \: \: \large{ \tt{ ↦\angle \: 4 = 180 \degree - 38 \degree = \boxed{ \tt{142 \degree}}}}$

$\large{ \tt{ \angle \: 1 = \angle \: 4 = \boxed{ \tt{142 \degree}( \text{Being \: vertical \: angles)}}}}$

$\large{ \tt{ \angle \: 8 = \angle \: 4 = \boxed{ \tt{142 \degree} \text{(Being \: corresponding \: angles)}}}}$

$\large{ \tt{ \angle \: 6 = \angle \: 1 = \boxed{ \tt{142 \degree} \text{(Being \:corresponding \: angles) }}}}$

$\large {\tt{ \angle \: 2 = \boxed{\tt{38 \degree}}\text{(Being \: corresponding \: angles)}}}$

$\large{ \tt{ \angle \: 3 = \boxed{\tt{38 \degree} }\text{(Being \: alternate \: angles)}}}$

$\large{ \tt{✺ \: TIPS} }:$

If you have planned for study at 8:00 and now it's 8:05 then don't wait for 9 : 00 , Start studying that subject right now ! ♪

$\large{ \tt{❃ \: LEARN \: ABOUT \: ALTERNATE \: , CORRESPONDING\:AND \: CO - INTERIOR \: ANGLES}} :$

brainly.com/question/17147541

ツ Hope I helped! ♡

☼ Have a wonderful day / evening ! ☃

# StayInAndExplore ! ☂

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8 0

3 years ago

AYOOO PLZ HELP ASAP!!!

tamaranim1 [39]

Answer:

B.

Step-by-step explanation:

Well we know that

$224=2^{5} *7$

so we can get the 2 outside of the radical

$x^{11} =(x^{5} )^{2} *x$

and we can get the x^2 outside too.

$y^8=y^5*y^3$

and we also can get y outside.

so we have:

$2x^{2}y\sqrt[5]{7xy^3}$

7 0

3 years ago