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andre [41]
2 years ago
14

(12.0) and (0.35) What’s the answer

Mathematics
1 answer:
Allushta [10]2 years ago
7 0

Answer:

37

Step-by-step explanation:

=sqrt((x2-x1)^2+(y2-y1)^2)=sqrt((0-12)^2+(35-0)^2)=sqrt(144+1225)=sqrt(1369)=37=37

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Sove for q.<br> s = 4p + 4q
sergey [27]
S=4P+4Q S=4(P+Q) S/4=P+Q S/4-P=Q Q=S/4-P
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3 years ago
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A rectangular parking lot has a perimeter of 820 ft. The area of the parking lot measures 42,000 ft2. What is a dimension of the
dalvyx [7]

To solve the problem we must know about quadratic equations.

<h2>Quadratic Equation</h2>

A quadratic equation is an equation that can be written in the form of

ax²+bx+c.

Where a is the leading coefficient, and

c is the constant.

The breadth of the rectangle is 200 ft, while the length is 210 ft.

<h2>Explanation</h2>

Given to us

  • Area of the parking lot = 42,000 ft²
  • Perimeter of the parking lot = 820 ft

<h3>Area of the parking lot</h3>

Area of the parking lot = Area of the rectangle

42,000 ft² = Length x Breadth

Solving for L,

42,000 = L \times B\\\\&#10;L = \dfrac{42,000}{B}

<h3>Perimeter of the parking lot</h3>

Perimeter of the parking lot = Perimeter of the rectangle

820 ft. = 2(Length + Breadth)

820 ft. = 2(L+ B)

2(L+ B) = 820\\\\&#10;(L+B) = \dfrac{820}{2}\\\\&#10;(L+B) = 410

Substituting the value of L,

(L+B) = 410\\\\&#10;(\dfrac{42,000}{B}) +B = 410\\\\&#10;42000 + B^2 = 410B\\\\&#10;B^2 -410B +42000 = 0

<h3>Quadratic Expression</h3>

Solving the quadratic Expression,

B^2 -410B +42000 = 0\\\\&#10;(B-210)(B-200)=0

Equation the factors against zero,

B-210=0

B = 210

B-200=0

B = 200

Hence, the breadth of the rectangle is 200ft, while the length is 210 ft.

Learn more about Quadratic Expression:

brainly.com/question/10025464

4 0
2 years ago
Given that y=x^(1/3) , use calculus to determine an approximate value for ∛8030
Alex777 [14]
F(x) = x^(1/3)
f(8000) = 8000^(1/3) = 20

f'(x) = 1/3 * x^(-2/3)
f'(x) = 1/(3x^(2/3))
f'(8000) = 1/(3*8000^(2/3)) = 1/(3*400) = 1/1200

Linear approximation for f(x) about x = 8000
L(x) = f(8000) + f'(8000) (x−8000)
L(x) = 20 + 1/1200 (x−8000)

8030^(1/3) ≈ L(8030)
= 20 + 1/1200 (8030−8000)
= 20 + 30/1200
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8 0
2 years ago
What else would need to be congruent to show that AABC=A DEF by the
Pepsi [2]

Answer:

D. AC ≅ DF

Step-by-step explanation:

According to the AAS Theorem, two triangles are considered congruent to each other when two angles and a mon-included side of one triangle are congruent to two corresponding angles and a corresponding non-included side of the other.

Thus, in the diagram given:

<A and <B in ∆ABC are congruent to corresponding angles <D and <E in ∆DEF.

The only condition left to be met before we can conclude that both triangles are congruent by the AAS Theorem is for a mon-included side AC to be congruent to corresponding non-included side DF.

So, AC ≅ DF is what is needed to make both triangles congruent.

7 0
3 years ago
The figure of Circle A shown below has diameter PR which intersects QS at point B and the measurements shown. Calculate the foll
nata0808 [166]

The figure is an illustration of the relationship between the angles in a circle and arc

<h3>The measure of angle PSQ</h3>

From the figure, the arc PQ is subtended by the angle PAQ.

This means that:

PQ = ∠PAQ

Given that ∠PAQ = 130, it means that:

Arc PQ = 130

The measure of PSQ is then calculated using:

∠PSQ = 0.5 * Arc PQ ----- inscribed angle is half a subtended angle.

This gives

∠PSQ = 0.5 * 130

∠PSQ = 65

Hence, the measure of ∠PSQ is 65 degrees

<h3>The measure of arc QR</h3>

A semicircle measures 180 degrees.

This means that:

QR + PQ = 180

So, we have:

QR = 180 - PQ

Substitute 130 for PQ

QR = 180 - 130

QR = 50

Hence, the measure of QR is 50 degrees

<h3>The measure of arc RS</h3>

The measure of arc RS is then calculated using:

∠RPS = 0.5 * Arc RS ----- inscribed angle is half a subtended angle.

Where ∠RPS = 35

So, we have:

35 = 0.5 * Arc RS

Multiply both sides by 2

Arc RS = 70

Hence, the measure of RS is 70 degrees

<h3>The measure of angle AQS</h3>

In (a), we have:

∠PSQ = 65

This means that:

∠PSQ = ∠PSB = 65

So, we have:

∠PSB = 65

Next, calculate SBP using:

∠SBP + ∠BPS + ∠PSB = 180 ---- sum of angles in a triangle.

So, we have:

∠SBP + 35 + 65 = 180

∠SBP + 100 = 180

This gives

∠SBP = 80

The measure of AQS is then calculated using:

AQS = AQB = 180 - (180 - SBP) - (180 - PAQ)

This gives

AQS = 180 - (180 - 80) - (180 - 130)

Evaluate

AQS = 30

Hence, the measure of AQS is 30 degrees

<h3>The measure of arc PS</h3>

A semicircle measures 180 degrees.

This means that:

PS + RS = 180

This gives

PS = 180 - RS

Where RS = 70

So, we have:

PS = 180 - 70

Evaluate

PS = 110

Hence, the measure of arc PS is 110 degrees

Read more about circles and arcs at:

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#SPJ1

6 0
2 years ago
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