(x+6)^(1/2)-5=x+1
(x+6)^(1/2)=x+6
((x+6)^(1/2))^2=(x+6)^2
x+6=x^2+12x+36
0=x^2+11x+30
(-11+(11^2-4(1)(30))^(1/2))/2
(-11+((1)^(1/2))/2
(-11+1)/2=-5
(-11-1)/2=-6
((-6)+6)^1/2-5=(-6)+1
(0^(1/2))-5=-5
-6 is non-extraneous
((-5)+6)^1/2-5=(-5)+1
(1^1/2)-5=-4
1-5=-4
-4=-4
-5 is non-extraneous
Answer:
180psi
Step-by-step explanation:
Step one:
given data
P1= 900 psi
T1= 350°C
P2=?
T2=70°C
Required
The final pressure P2
<em>Gay-Lussac's Law: The Pressure Temperature Law. This law states that the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature. With an increase in temperature, the pressure will go up</em>
Applying the expression
P1/T1= P2/T2
substitute:
900/350= P2/70
2.57=P2/70
cross multiply
P2= 2.57*70
P2=180psi
Answer:
<u>3 5 = 16</u>
<u> 3 = 3 16</u>
<u> 6 = 16</u>
<u> 6 = -4</u>
<u> x = -4/6</u>
each line has the number of boxes to be filled
Your answer is 110. You take 10 and divide it by 750. = 75 then you take 75. Divided 8250. = 110
Answer:
x = 3
Step-by-step explanation:
6x + 7 = 9x - 2
-3x = -9
x = 3
