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3 years ago

6

I don't know who needs to hear this but I wanted to hopefully reach out to someone.

1 answer:

lora16 [44]3 years ago

8 0

Answer:

oh my- this actually made me happy-

Step-by-step explanation:

You might be interested in

A truck driver has a route that takes him 125 miles each way each day that he works. If he makes 15 roundtrips on this route per

7nadin3 [17]

Answer: 3,750 miles

Step-by-step explanation:

Route takes him 125 miles each way so in a day he travels:

= 125 + 125

= 250 miles

He made 15 roundtrips so total miles is:

= 15 * 250

= 3,750 miles

3 0

2 years ago

Please can you answer it because I need the answer

andre [41]

Answer:

For x^2 + 5x - 14 = 0

x1= -7, x2 = 2

For x^2 + 5x + 6 = 0

x1 = -3, x2 = -2

Step-by-step explanation:

Pls see attached....

7 0

3 years ago

A map has a scale of 1/2 inch= 20miles quinn wants to travel an actual distance

inessss [21]

Answer:

1.75 inches or 1 3/4inches

Step-by-step explanation:

A map has a scale of ½½inch=20mles. Quinn wants to travel an actual distance of 70miles. What will the length on the map be?

70/20

=7/2

=1/2×7/2

=7/4

=1 3/4 inches

in decimal its 1.75 inches

5 0

2 years ago

Please solve 5 f <br> (Trigonometric Equations)<br> #salute u if u solved it

Zanzabum

Answer:

$\beta=45\degree\:\:or\:\:\beta=135\degree$

Step-by-step explanation:

We want to solve $\tan \beta \sec \beta=\sqrt{2}$ , where $0\le \beta \le360\degree$ .

We rewrite in terms of sine and cosine.

$\frac{\sin \beta}{\cos \beta} \cdot \frac{1}{\cos \beta} =\sqrt{2}$

$\frac{\sin \beta}{\cos^2\beta}=\sqrt{2}$

Use the Pythagorean identity: $\cos^2\beta=1-\sin^2\beta$ .

$\frac{\sin \beta}{1-\sin^2\beta}=\sqrt{2}$

$\implies \sin \beta=\sqrt{2}(1-\sin^2\beta)$

$\implies \sin \beta=\sqrt{2}-\sqrt{2}\sin^2\beta$

$\implies \sqrt{2}\sin^2\beta+\sin \beta- \sqrt{2}=0$

This is a quadratic equation in $\sin \beta$ .

By the quadratic formula, we have:

$\sin \beta=\frac{-1\pm \sqrt{1^2-4(\sqrt{2})(-\sqrt{2} ) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{1^2+4(2) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{9} }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm3}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{2}{2\cdot \sqrt{2} }$ or $\sin \beta=\frac{-4}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{1}{\sqrt{2} }$ or $\sin \beta=-\frac{2}{\sqrt{2} }$

$\sin \beta=\frac{\sqrt{2}}{2}$ or $\sin \beta=-\sqrt{2}$

When $\sin \beta=\frac{\sqrt{2}}{2}$ , $\beta=\sin ^{-1}(\frac{\sqrt{2} }{2} )$

$\implies \beta=45\degree\:\:or\:\:\beta=135\degree$ on the interval $0\le \beta \le360\degree$ .

When $\sin \beta=-\sqrt{2}$ , $\beta$ is not defined because $-1\le \sin \beta \le1$

4 0

3 years ago

Which angles are complementary<br> to <1. Select all that apply.

lbvjy [14]

Answer:

∠5

Step-by-step explanation:

Complementary angles are angles that:

sum to 90°
make a right angle

Given this information, angles 2, 3, and 4 are already right angles. That leaves angle 5 and angle 1 to be complementary with each other, as they form a right angle.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

~ ren

4 0

2 years ago