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mezya [45]
3 years ago
5

Hi my name is Jasmin I've been having trouble with math. I'm learning how to Multiply fractions, I want to know how to get the c

orrect answer for this problem,...Jason ran 5/7 of the distance around a track, Sarah ran 4/5 of Jasons distance. What fraction of the distance around the track did Sarah run?

Mathematics
2 answers:
Kipish [7]3 years ago
5 0
5/7 x 4/5 it will be 20/35 if you simplify it will be 4/7
Keith_Richards [23]3 years ago
4 0
Attached a picture
you may ask any question????

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8090 [49]

For f(x+h) - \dfrac{f(x)}{h} reading the fraction like f(x)/h only (f(x+h) start fraction f(x) / h end fraction), the answer is -x^2/y + x^2 + 2x + y + y^2 - 1/y + 1

5 0
3 years ago
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goldenfox [79]

Answer:

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7 0
3 years ago
Find the surface area of each shipping package. Which package has the greater surface area? Does the same package have a greater
Kryger [21]

Answer:

  • greater area: A
  • no, B has the greater volume

Step-by-step explanation:

The relevant area and volume formulas are ...

  A = 2(LW +H(L +W))

  V = LWH

When there are multiple instances of the calculations to be done, it is convenient to let a spreadsheet do them. The results are attached.

Figure A has the larger area.

Figure B has the larger volume.

__

<em>Additional comment</em>

The more "cube-like" the prism is, the less area it will have for the same volume. Here, package B is more "cube-like" than package A. (The ratio of largest-to-smallest dimensions is smaller for package B.)

3 0
2 years ago
Jim is trying to improve his speed on the track so he can qualify for the State Championships. As he is running, he goes from 70
kumpel [21]

Answer:

His acceleration is \frac{1}{15} meters per seconds²

Step-by-step explanation:

Acceleration is the rate of change of the speed

The formula of acceleration is a=\frac{v_{f}-v_{i}}{t} , where

  • v_{f} is the final speed
  • v_{i} is the initial speed
  • The unit of the acceleration is meters/second²

∵ Jim goes from 70 meters/minute (beginning speed) to

   106 meters/minute (final speed) in 9 seconds

∴ His initial speed v_{i} = 70 meters/minute

- Change it the meter per second

∵ 1 minute = 60 seconds

∴ \frac{70}{(1)(60)}=\frac{70}{60}=\frac{7}{6}  meters/second

∴ v_{i} = \frac{7}{6}  meters/second

∵ His final speed v_{f} = 106 meters/minute

- Change it the meter per second

∴ \frac{106}{(1)(60)}=\frac{106}{60}=\frac{53}{30}  meters/second

∴ v_{f} = \frac{53}{30}  meters/second

∵ The time of the change of his speed is 9 seconds

∴ t = 9

∵ The formula of acceleration is a=\frac{v_{f}-v_{i}}{t}

- Substitute the values of t, v_{i}  and v_{f} in the formula above

∴  a=\frac{\frac{53}{30}-\frac{7}{6}}{9}=\frac{1}{15}

∴ His acceleration is \frac{1}{15} meters per seconds²

3 0
3 years ago
The magnitude, M, of an earthquake is defined to be M = log StartFraction I Over S EndFraction, where I is the intensity of the
uranmaximum [27]

The equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake is \rm M = log\left ( \dfrac{10S}{S}\right ).

Given

The magnitude, M, of an earthquake is defined to be M = log StartFraction I Over S EndFraction, where I is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and S is the intensity of a "standard" earthquake, which is barely detectable.

<h3>The magnitude of an earthquake</h3>

The magnitude of an earthquake is a measure of the energy it releases.

For an earthquake with 1,000 times more intense than a standard earthquake.

The equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake is;

\rm M =log \dfrac{I}{S}\\\\M = log \dfrac{10s}{s}\\\\M=log 10\\\\M =1

Hence, the equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake is \rm M = log\left ( \dfrac{10S}{S}\right ).

To know more about the magnitude of earthquakes click the link given below.

brainly.com/question/1337665

5 0
2 years ago
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