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Marrrta [24]
3 years ago
15

The perimeter of a rectangle is 48 cm. The length is 6cm less than twice the width. Which system would model this situation and

what are the lengths and the width
Mathematics
1 answer:
fenix001 [56]3 years ago
7 0
The easiest way to solve this question would be to subtract the 6 from the 48 which results in 42. Then because the length is twice it’s width we divide the 42 by 3 which gives us 14. Therefore the width is 14 and the length is double of fourteen which is 28
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Answer:

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Step-by-step explanation:

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Ronch [10]
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x-1=5x+10
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2) x-1=-(5x+10)

x-1=-(5x+10)
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we have two  possible solutions:
solution₁;       x=-11/4
solution₂:       x=-3/2

we check it out:
1) x=-11/4
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[-11/4  - 1]=5(-11/4)+10
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[-3/2  - 1]=5(-3/2)+10
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Therefore:

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