Question

The perimeter of a rectangle is 48 cm. The length is 6cm less than twice the width. Which system would model this situation and what are the lengths and the width

Answer 1

The easiest way to solve this question would be to subtract the 6 from the 48 which results in 42. Then because the length is twice it’s width we divide the 42 by 3 which gives us 14. Therefore the width is 14 and the length is double of fourteen which is 28